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3 years ago

What is the solution to the inequality below?

Mathematics

1 answer:

madam [21]3 years ago

8 0

Answer:

C. x < 25 and x ≥ 0

Step-by-step explanation:

Fastest and easiest way to do this is to graph the inequality and find out the lines.

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In ⊙P, QR≅ST. Which statement must be true? Select all that apply.

den301095 [7]

The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π

<h3>The circle with center P</h3>

Given that the circle has a center P

It means that lengths PQ, PR, PS and PT

From the question, we understand that QR = ST.

This implies that triangles QRP and STP are congruent.

i.e. △QRP ≅ △STP is true

<h3>The length of the minor arc</h3>

The given parameters are:

Angle, Ф = 99

Radius, r = 1

The length of the arc is:

L = Ф/360 * 2πr

So, we have:

L = 99/360 * 2π * 1

Evaluate

L = 198/360π

Divide

L = 11/20π

Hence, the length of the minor arc is 11/20π

Read more about circle and arcs at:

brainly.com/question/3652658

#SPJ1

5 0

2 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

What is 2.5 simplified

Nuetrik [128]

Step-by-step explanation:

$2.5 = \frac{25}{10} = \frac{5 \times 5}{2 \times 5} = \frac{5}{2} \\$

3 0

3 years ago

Alex got 27 questions out of 30 correct. what present of the questions did he get correct?(use fish method)

Novosadov [1.4K]

if we take 30 to be the 100%, what is 27 off of it in percentage?

$\begin{array}{ccll} amount&\%\\ \cline{1-2} 30 & 100\\ 27& x \end{array} \implies \cfrac{30}{27}=\cfrac{100}{x} \\\\\\ \cfrac{10}{9}=\cfrac{100}{x}\implies 10x=900\implies x=\cfrac{900}{10}\implies x=90$

4 0

2 years ago

66% of what number is 33

horsena [70]

Answer: 21.78

Step-by-step explanation: Multiply 33 by .66. You will get 21.78.

5 0

3 years ago

Read 2 more answers