How many liters of a 0.26 M solution of K2(MnO4) would contain 75 g of K2(MnO4)?
1 answer:
Answer:
V = 1.46 L.
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to solve this problem based off the definition of molarity, as the moles of solute divided by the volume in liters of solution:
In such a way, we first calculate the moles of K2(MnO4) by using its molar mass of 197.132 g/mol:
Next, we solve for the volume in the equation of molarity to obtain:
And plug in as follows:
Regards!
You might be interested in
Explanation:
Usually most cells that carry anaerobic respiration utilize the Glycolysis pathway because it does not require oxygen. It is also believed it is the ancient metabolic pathway by utilized by primordial cells when the earth's atmosphere was not mainly oxygen,
Glycolysis consumes 2 ATPs (during the conversion of Glucose to Fructose 1,6 bisphosphate ) but produces a gross $ ATPs. It, therefore, has a net ATP of 2. This is inefficient when compared to the Krebs cycle that utilizes oxygen to produce 34 ATPs. Anaerobic respiration produces pyruvate. This pyruvate is broken down into an organic acid like lactic acid which is excreted from the cell, which is why fermented food tastes sour.
Learn More:
For more on Glycolysis metabolic pathway check out;
#LearnWithBrainly
