Answer:
0.005 M
Explanation:
Given data:
volume of sample solution ( volume of D ) = 5.0 mL
volume of added stock solution ( V1 ) = 5.0 mL
concentration of added stock solution ( N1 ) = 0.02 M
Total volume of concentration ( V2 )= 10 mL = ( 5.0 mL + 5.0mL)
concentration of Total volume of sample ( C2 ) = 0.01
N2 = ( N1V1 ) / V2
= ( 0.02 * 5 ) / 10 = 0.01 m
absorbance of sample solution ( A1 ) = 0.10
absorbance of additional sample solution ( A2 ) = 0.20
attached below is the remaining part of the detailed solution
Answer:
the partial pressure of the O2 is 0.167 atm
Explanation:
The computation of the partial pressure of the O2 is shown below:
As we know that
P = P_N2 + P_O2 + P_CO2
P_O2 = P - P_N2 - P_CO2
= (1.007 - 0.79 - 0.05)
= 0.167 atm
Hence, the partial pressure of the O2 is 0.167 atm
we simply applied the above formula
Answer:
It will be a pure substance (compound) because chemical composition of sugar crystals will be the same whether obtained from sugarcane or from beet root.
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To calculate the average atomic mass, multiply the fraction by the mass number for each isotope, then add them together.