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vladimir2022 [97]
3 years ago
10

Consider the following reaction: CO(g)+2H2(g) <--> CH3OH(g).

Chemistry
1 answer:
Andrew [12]3 years ago
4 0

Answer:

123 is the equilibrium constant for the reaction.

Explanation:

CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)

Equilibrium concentration of reactants :

[CO]=0.115 M,[H_2]=0.116 M

Equilibrium concentration of products:

[CH_3OH]=0.190 M

The expression of an equilibrium constant is given by :

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

K_c=\frac{0.190 M}{0.115 M\times (0.116 M)^2}

K_c=122.78 \approx 123

123 is the equilibrium constant for the reaction.

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See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

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B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

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