Question

Consider the following reaction: CO(g)+2H2(g) <--> CH3OH(g).

Answer 1

Answer:

123 is the equilibrium constant for the reaction.

Explanation:

$CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)$

Equilibrium concentration of reactants :

$[CO]=0.115 M,[H_2]=0.116 M$

Equilibrium concentration of products:

$[CH_3OH]=0.190 M$

The expression of an equilibrium constant is given by :

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

$K_c=\frac{0.190 M}{0.115 M\times (0.116 M)^2}$

$K_c=122.78 \approx 123$

123 is the equilibrium constant for the reaction.