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Anna71 [15]
3 years ago
11

Factor the expression using the GCF. 6x + 42

Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer: 6x + 42 +=78

.

Step-by-step explanation:

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Find the equation of the line whose x-intercept is 8 and y-intercept is -2. write the equation in slope-intercept form.
goldfiish [28.3K]
Find the slope, m = (change in y) / (change in x)

                     0-(-2)
Here, m = ------------- = 1/4
                     8 - 0
y-k = m(x-h) becomes         y+2 = (1/4)(x), or y = (1/4)x - 2

Then the desired equation is   y = (1/4)x - 2 (slope-intercept form)
7 0
3 years ago
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T(t)T, models the daily high temperature (in Celsius) in Santiago, Chile, t days after the hottest day of the year. Here, t is e
erma4kov [3.2K]

Answer:

the answer is 262 days

Step-by-step explanation:

8 0
3 years ago
The sum of two twin primes is 60. What are the numbers
Fudgin [204]
Its 29 and 31. thats the answer
7 0
4 years ago
Read 2 more answers
Can somebody help me please
AnnyKZ [126]

It's an isosceles triangle so angles A and BCA are congruent.  

Angle BCA is the supplement of BCD, so 180-109 = 71.

Angle A is congruent to that, so A=71 degrees.

Let's see if we can get that in the format they want, kind of as a proof.

1.  ∠BCD=109° Reason: Given

2. AB ≅ BC      Reason: Given

3. ∠BCA = 71°  Reason: Linear pairs are supplementary

4. ΔABC is isosceles.   Reason: Definition of isosceles

5. ∠A ≅ ∠BCA   Reason: Isoceles triangle theorem

6. ∠A = 71°         Reason: Def congruent

Answer: 71 degrees

5 0
3 years ago
Suppose the test scores on an exam show a normal distribution with a mean of 82 and a standard deviation of
Zanzabum

Answer:

a) Between 74 and 90

b) 81.86% of the scores are between 78 and 90

Step-by-step explanation:

a) According to the Empirical Rule, in a normal distribution, 95% of the data are within 2 standard deviations of the mean. Therefore, the range that 95% of the scores fall in is between 82-4(2)=74 and 82+4(2)=90.

b) The percent of scores that are between 78 and 90 is: normalcdf(lower,upper,μ,σ) = normalcdf(78,90,82,4) = 0.8185946784 ≈ 0.8186, or about 81.86% of the scores.

5 0
3 years ago
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