b^5 divided by a^2
I don't know how to do the fraction thingy on this thing but to explain it, since a has a negative exponent it has to move to the denominator for this equation to work. That is why the b^2 is on top and the a^2 on the bottone. Once the a^-2 goes to the bottom, it loses the negative sign.
6636 has 3 circle so 6636=3
8118 has 4 circle so 8118=4
2212 has 0 circle so 2212=0
8688 has 7 circle 8688=7
5971 has 1 circle 5971=1
the answer is 11/6 as a mixed number in simplest form
The answer to 3) is: x = ±7
Break down the problem into these 2 equations:
x/7 = 1 and -x/7 = 1
Then solve both equation and collect all solutions.
Let me know if this helped you! Good luck Bella4992!