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alexandr402 [8]
4 years ago
7

Stuck? helppp aspappp

Mathematics
2 answers:
levacccp [35]4 years ago
5 0
Here’s what I found, good luck bella.

Keith_Richards [23]4 years ago
3 0

The answer to 3) is: x = ±7

Break down the problem into these 2 equations:

x/7 = 1 and -x/7 = 1

Then solve both equation and collect all solutions.

Let me know if this helped you! Good luck Bella4992!

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Can you please help me figure out this answer? Please and thank you
galben [10]

Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.

The formula for P is P = 2W + 2L.

Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:

P = 2(3 1/2 yds) + 2(4 2/3 yds)

= 7 yds + 9 1/3 yds = 16 1/3 yds, total.

7 0
3 years ago
A clerk at a local camera shop earns a 5% commission on all sales. How much commission does the clerk earn on a $500 sale?
Karolina [17]

Answer:

she earns $25.00 commission

Step-by-step explanation:

.05×500=25

5 0
3 years ago
10) Solve the inequality to find how many hours until the temperature will
Leno4ka [110]
I Think The answer is a I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
7 0
3 years ago
Read 2 more answers
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
Please i need this due now and DO NOT GIVE ME A LINK FOR THE ANSWER
lana66690 [7]

Answer:

Y = -3(x - 5/6)^2 - 59/12 and  x = 5±i√59/6

Step-by-step explanation:

Pls give brainllest

8 0
3 years ago
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