3 years ago

(b) Factorise fully 9b-3b squared

Mathematics

1 answer:

shepuryov [24]3 years ago

7 0

Answer:

Step-by-step explanation:

b(9-3)

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Step 1: Write out the function given

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Step 2: Interprete the question given

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The question requested we find the summation of the first five terms for f(k/2), when k is 1, 2, 3, 4, and 5

Step 3: Find the expression for f(k/2)

$\begin{gathered} f(\frac{k}{2})=3(\frac{k}{2})^2-\frac{k}{2} \\ =\frac{3k^2}{4}-\frac{k}{2} \\ =\frac{3k^2-2k}{4} \end{gathered}$ $\begin{gathered} =\frac{3(1)^2-2(1)}{4}+\frac{3(2)^2-2(2)}{4}+\frac{3(3)^2-2(3)}{4}+\frac{3(4)^2-2(4)}{4}+\frac{3(5)^2-2(5)}{4} \\ =\frac{1+8+21+40+65}{4} \\ =\frac{135}{4} \\ =33.75 \end{gathered}$

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