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iris [78.8K]
3 years ago
11

Find the perimeter of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

Mathematics
1 answer:
choli [55]3 years ago
6 0

Given:

The vertices of a quadrilateral ABCD are A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

To find:

The perimeter of quadrilateral ABCD.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(4-0)^2+(1-4)^2}

AB=\sqrt{(4)^2+(-3)^2}

AB=\sqrt{16+9}

AB=\sqrt{25}

AB=5

Similarly,

BC=\sqrt{(1-4)^2+(-3-1)^2}

BC=5

CD=\sqrt{(-3-1)^2+(0-(-3))^2}

CD=5

And,

AD=\sqrt{(-3-0)^2+(0-4)^2}

AD=5

Now, the perimeter of the quadrilateral ABCD is:

P=AB+BC+CD+AD

P=5+5+5+5

P=20

Therefore, the perimeter of the quadrilateral ABCD is 20 units.

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Adding up the two equivalent fractions

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Equation at the end of step  2  :

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Step  3  :

When a fraction equals zero :

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

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Now, on the left hand side, the  3  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

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Solving a Single Variable Equation :

<u>Solve  :</u>    x-45 = 0

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One solution was found :

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