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iris [78.8K]
2 years ago
11

Find the perimeter of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

Mathematics
1 answer:
choli [55]2 years ago
6 0

Given:

The vertices of a quadrilateral ABCD are A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

To find:

The perimeter of quadrilateral ABCD.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(4-0)^2+(1-4)^2}

AB=\sqrt{(4)^2+(-3)^2}

AB=\sqrt{16+9}

AB=\sqrt{25}

AB=5

Similarly,

BC=\sqrt{(1-4)^2+(-3-1)^2}

BC=5

CD=\sqrt{(-3-1)^2+(0-(-3))^2}

CD=5

And,

AD=\sqrt{(-3-0)^2+(0-4)^2}

AD=5

Now, the perimeter of the quadrilateral ABCD is:

P=AB+BC+CD+AD

P=5+5+5+5

P=20

Therefore, the perimeter of the quadrilateral ABCD is 20 units.

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