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BartSMP [9]
3 years ago
13

Is this statement true or false? Gymnosperms reproduce using seeds, but angiosperms do not.

Chemistry
1 answer:
spayn [35]3 years ago
3 0

Answer:

FALSE!

Explanation:

Gymnosperms do use seeds but are exposed like the pine cones of pines. Angiosperms still have seeds, however, they flower or fruit.

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Which electromagnetic wave type has frequencies higher than the violet of visible light?
belka [17]

Answer:

Ultraviolet means “above violet.” The electromagnetic frequencies of ultraviolet radiation (UV) extend upward from violet, the highest-frequency visible light.

hope this helps

7 0
3 years ago
Which of the following is a major consequence of the shifting of the Intertropical Convergence Zone (ITCZ)? A. monsoon rains in
Xelga [282]
The shifting of the Intertropical Convergence Zone (ITCZ) results to <span>A. monsoon rains in South Asia. The ITCZ is a region on Earth where the Northern and Southern hemispheres meet, causing the trade winds from both regions to meet. This causes a belt of low pressure, making the region prone to heavy rainfall or monsoon rains.</span>
8 0
3 years ago
Which statement correctly describes a covalent bond?  The valence electrons are joined in a shell around the atoms. The valence
Vedmedyk [2.9K]
The valence electrons are shared between the atoms
4 0
4 years ago
If 35 ml of 6.0 m h2so4 was spilled, calculate the minimum mass of nahco3 that must be added to the spill to neutralize the acid
belka [17]

The balanced equation between the H_2SO_4 and NaHCO_3 is:

H_2SO_4+2NaHCO_3\rightarrow Na_2SO_4+2CO_2+2H_2O

Formula of molarity is:

Molarity = \frac{Moles of solute}{Volume of solution in Liters}

Molarity = 6.0 M, Volume = 35 mL = 0.035 L

Substituting the values,

6 = \frac{Moles of solute}{0.035}

Moles of solute = 0.035 L\times 6 mol/L = 0.21 mole

So, number of moles of H_2SO_4 is 0.21 mole.

From the balanced equation it is clear that for 1 mole of H_2SO_4, 2 moles of NaHCO_3 are required.

Hence, 0.21 mole of H_2SO_4  = 2\times 0.21 mole = 0.42 mole of NaHCO_3

Molar mass of NaHCO_3 = 84.007 g/mol

So, the mass of NaHCO_3 = 84.007 g/mol \times 0.42 mol = 35.283 g




6 0
3 years ago
- prediction
kolezko [41]

Answer:

theory

Explanation:

Fits all criteria

- Hope that helps! Please let me know if you need further explanation.

8 0
3 years ago
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