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3 years ago

what mass of small stones would be needed to make the strongest concrete? give a reason for your awnser.

Chemistry

1 answer:

VikaD [51]3 years ago

3 0

Answer:

For a good consert mix aggregate needed to the clean hard strong partical free of absorb chemicals or coating clay and other fine materials

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Consider an electron with charge âˆ’eâˆ’e and mass mmm orbiting in a circle around a hydrogen nucleus (a single proton) with cha

PtichkaEL [24]

Answer:

Explanation:

The net force on electron is electrostatic force between electron and proton in the nucleus .

Fc = $\frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}$

This provides the centripetal force for the circular path of electron around the nucleus .

Centripetal force required = $\frac{m\times v^2}{r}$

$\frac{m\times v^2}{r}=\frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}$

$v^2=\frac{e^2}{4\pi \epsilon m r}$

$v=(\frac{e^2}{4\pi \epsilon m r})^{\frac{1}{2} }$

5 0

2 years ago

How many grams of octane (C8H18) must be burned to produce 300.0g of CO2?

nika2105 [10]

Answer:

$m_{C_8H_{18}}=85.67gC_8H_{18}$

Explanation:

Hello there!

In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:

$m_{C_8H_{18}}=300.0gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molC_8H_{18}}{25molO_2}*\frac{114.22gC_8H_{18}}{1molC_8H_{18}} \\\\m_{C_8H_{18}}=85.67gC_8H_{18}$

Regards!

6 0

2 years ago

Round the nearseat whole number how many neutrons on average are in atom of osmium?

Anettt [7]

Answer:

jdjdjdhjxjxjchxjxjkxjxjxhxnxkjcjcjcj

Explanation:

sorry i just need point lolllllllllll

7 0

3 years ago

Question 19-20<br> I’m not really sure, can someone help me

Nesterboy [21]

Hi my name is Jaleesa The answer = -1

6 0

3 years ago

You have 100 g of Pb(NO3)2. How many moles is this?

topjm [15]

Answer:

0.302 moles

Explanation:

Data given

Mass of Pb(NO₃)₂ = 100 g

Moles of Pb(NO₃)₂ = ?

Solution:

To find mole we have to know about molar mass of Pb(NO₃)₂

So,

Molar mass of Pb(NO₃)₂ = 207 + 2[14 + 3(16)]

= 207 + 2[14 + 48]

= 207 + 124

Molar mass of Pb(NO₃)₂ = 331 g/mol

Formula used :

no. of moles = mass in grams / molar mass

Put values in above formula

no. of moles = 100 g / 331 g/mol

no. of moles = 0.302 moles

no. of moles of Pb(NO₃)₂ = 0.302 moles

7 0

2 years ago