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Sedbober [7]
1 year ago
8

In which case would an electron experience the greatest effective nuclear charge? not all cases describe an atom in the ground s

tate.
Chemistry
1 answer:
lisabon 2012 [21]1 year ago
5 0

One electron in an atom experiences the entire positive charge of the nucleus. Coulomb's law can be used in this situation to determine the effective nuclear charge.

In contrast, the outside electrons in an atom with many electrons are drawn to the positive nucleus and repelled by the negatively charged electrons at the same time. The force between two stationary, electrically charged particles can be measured using Coulomb's law inverse-square law, also known as Coulomb's law. Conventionally, the electric force between two charged objects at rest is referred to as the Coulomb force or electrostatic force.

The electron is a subatomic particle with the symbol e or with an electric charge of one elementarily negative charge. The lepton particle family's first generation includes electrons.

Learn more about Coulomb's law here

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22.4 L of hydrogen is taken in a cylinder at zero degree Celsius and at one atm. This gas is transferred to a cylinder of 11.2 L
geniusboy [140]

Answer:

  2 Atm; 2.016 g

Explanation:

Changing the volume without changing the temperature or mass only changes the pressure. Volume and pressure are inversely proportional so halving the volume will double the pressure.

P = 1 Atm, T = 0 °C are "standard" temperature and pressure (STP). The volume of 1 mole of gas is 22.4 L under these conditions. That means the amount of hydrogen gas in the cylinder is 1 mole, so has a mass of 2.016 g.

After the volume reduction, the pressure is 2 Atm, and the mass remains 2.016 g.

7 0
2 years ago
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Answer:

S

Explanation:

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2 years ago
Creating nuclear energy produces large amounts of radioactive waste.
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2 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

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2 years ago
What are the 2 layers of continental crust called?​
noname [10]

Answer:

silica + aluminum or silica +magnetism

Explanation:

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