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Natalija [7]
3 years ago
7

Answers: A and B B and D A and C B and C

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0

Answer:

A and B

I hope this helps you

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I’m really confused on what the answer is supposed to be
kozerog [31]

Answer:

<u>-4 < x < -2</u>

Step-by-step explanation:

Taking the left part of the inequality :

  • 8 > 4 - x
  • x > -4

Taking the right part of the inequality :

  • 4 - x > 6
  • -x > 2
  • x < -2

Solution :

  • <u>-4 < x < -2</u>
6 0
2 years ago
Select all of the following statements that are true.
-Dominant- [34]

Answer:

3. Correlation coefficients can be represented by the variable r

Step-by-step explanation:

Correlation coefficients show if there is a strong or weak  positive or negative relationship, or if there is no relationship between the variables.

Correlation coefficients are negative when the relationship is inversely proportional and positive when the relationship is proportional.

Correlation coefficients can be any value less than or equal to 1 or greater than  or equal to -1.​

7 0
3 years ago
The present shown below is a cube.
anastassius [24]

Answer:

SA = 2400 cm²

Step-by-step explanation:

SA of a cube = S² x 6 (the number of its faces)

SA = 20² x 6

SA = 400 x 6

SA = 2400 cm²

8 0
3 years ago
What is the similarity ratio of PQR to VXM?
Nastasia [14]

Answer:

3

Step-by-step explanation:

The correct answer is:

3

Explanation

review

△WXY~△GEF.

6

3

6

Y

X

W

2

1

2

F

E

G

What is the similarity ratio of △WXY to △GEF?

Simplify your answer and write it as a proper fraction, improper fraction, or whole number.

If two triangles are similar, their similarity ratio is the ratio between a side length in the first triangle and the corresponding side length in the second triangle.

solve

Look at the triangles.

6

3

6

Y

X

W

2

1

2

F

E

G

The similarity ratio of △WXY to △GEF is the ratio between a side length in △WXY and the corresponding side length in △GEF. So, the similarity ratio is  

WX

EG

=

3

1

=3.

4 0
3 years ago
I need trigometry help
Alex Ar [27]
A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.

4 0
3 years ago
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