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ValentinkaMS [17]
3 years ago
11

Which answer is correct

Mathematics
1 answer:
leva [86]3 years ago
4 0

Answer:

The answer is b

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75,575 how do the values of the digit differ in the number?
Vsevolod [243]

Answer:

<u>7</u>5,575 - ten-thousands place; this 7 is worth 70,000

7<u>5</u>,575 - thousands place; this 5 is worth 5,000

75,<u>5</u>75 - hundreds place; this 5 is worth 500

75,5<u>7</u>5 - tens place; this 7 is worth 70

75,57<u>5</u> - ones place; this 5 is worth 5



8 0
3 years ago
What's the equation for twice the difference of a number and 6 is equal to three times the sum of the number and 3
alukav5142 [94]
2(x-6)=3(x+3)

Let's solve your equation step-by-step.

<span><span>2<span>(<span>x−6</span>)</span></span>=<span>3<span>(<span>x+3</span>)

</span></span></span>Step 1: Simplify both sides of the equation.

<span><span>2<span>(<span>x−6</span>)</span></span>=<span>3<span>(<span>x+3</span>)

</span></span></span><span>Simplify: (Show steps)

</span><span><span><span>2x</span>−12</span>=<span><span>3x</span>+9

</span></span>Step 2: Subtract 3x from both sides.

<span><span><span><span>2x</span>−12</span>−<span>3x</span></span>=<span><span><span>3x</span>+9</span>−<span>3x

</span></span></span><span><span><span>−x</span>−12</span>=9

</span>Step 3: Add 12 to both sides.

<span><span><span><span>−x</span>−12</span>+12</span>=<span>9+12

</span></span><span><span>−x</span>=21

</span>Step 4: Divide both sides by -1.

<span><span><span>−x/</span><span>−1</span></span>=<span>21/<span>−1

</span></span></span><span>x=<span>−21

</span></span>Answer:

<span>x=<span>−<span>21</span></span></span>
8 0
3 years ago
What is thirty seven squared?
SSSSS [86.1K]
Ur answer is 1369 that is ur answer hope it helped and hope u pass
 


4 0
3 years ago
Read 2 more answers
Choose two ordered pairs that belong in quadrant two screenshot included
hjlf

Answer:

Answer (B) and (D)

Step-by-step explanation:

First we need to figure out: What is quadrant II about?

As said in the picture provided, quadrant II is in the upper left corner of a graph.

For a point to be in QII, the <em>x values need to be negative</em>, and <em>the y values need to be positive</em>.

B: (-4,2) and D: (-3,5) would belong in QII.

<em>Their x values are negative, and the y values are positive. </em>

<em>Therefore, </em><em>B and D would be the correct answers.</em>

<em />

5 0
3 years ago
Please help me with it is for homework<br><br> I really need help please help me
Solnce55 [7]

Answer:

See explanation

Step-by-step explanation:

Given two expressions:

2(s+0.5)+2(s+1.5)

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4

a. When s=0,

then

2(s+0.5)+2(s+1.5)=2(0+0.5)+2(0+1.5)=1+3=4

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 0+\dfrac{1}{4}\cdot 0\right)+4=4

b. When s=12,

then

2(s+0.5)+2(s+1.5)=2(12+0.5)+2(12+1.5)=2\cdot 12.5+2\cdot 13.5=25+27=52

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 12+\dfrac{1}{4}\cdot 12\right)+4=4(6+3)+4=4\cdot 9+4=36+6=40

c. Since the value of both expressions at s = 12 are different, the expressions are not equivalent.

6 0
3 years ago
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