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AfilCa [17]
3 years ago
11

PLEASE HELP! FOR BRAINLIEST!

Physics
1 answer:
Rasek [7]3 years ago
8 0

Answer:

B is the answer

Explanation:

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On sunday a strong gale blows near beth’s house. the best estimate for the wind speed is ____ miles/hour.
Rufina [12.5K]

Answer:

B. 47-54 miles/hour

Explanation:

Gale is a strong wind which is depicted by red warning flag. According to U.S. National Weather Service gale is a sustained surface wind. It is also used to refer winds from tropical coastal areas.

On the basis of force of wind gale is divided in four groups:

  1. Near gale   - 32-38 mph
  2. Gale            - 39-46 mph
  3. Strong gale - 47-54 mph
  4. Storm           - 55-63 mph
8 0
4 years ago
A single conducting loop of wire has an area of 7.26E-2 m2 and a resistance of 117 Ω. Perpendicular to the plane of the loop is
cricket20 [7]

Answer:

\frac{dB}{dt} = 591.45 T/s

Explanation:

i = induced current in the loop = 0.367 A

R = Resistance of the loop = 117 Ω

E = Induced voltage

Induced voltage is given as

E = i R

E = (0.367) (117)

E = 42.939 volts

\frac{dB}{dt} = rate of change of magnetic field

A = area of loop = 7.26 x 10⁻² m²

Induced emf is given as

E = A\frac{dB}{dt}

42.939 = (7.26\times 10^{-2})\frac{dB}{dt}

\frac{dB}{dt} = 591.45 T/s

3 0
3 years ago
Tần số của dao động duy trì
AfilCa [17]
Amman oak smoke skins kaons
8 0
3 years ago
An object moves along the x-axis according to the equation x = 3.00t2 – 2.00t + 3.00,
Ray Of Light [21]

Explanation:

x = 3.00t^{2} – 2.00t + 3.00,

Distance of object at 2 second,

x (t=2) = 3(4) - 2(2) +3

x (t=2) = 12-4 +3

x (t=2) = 11 m

Distance of object at 3 second,

x (t=3) = 3(9) - 2(3) +3

x (t=2) = 27 - 6 + 3

x (t=2) = 24 m

a) the average speed between t = 2.00 s and t = 3.00 s,

Average speed = \frac{Total distance}{ Total time}

Average speed = \frac{x (t=2) + x (t=3)}{3}

Average speed = \frac{24+11}{3}

Average speed = \frac{35}{3}

Average speed = 11.66 \frac{m}{s}

b) the instantaneous speed at t = 2.00 s and t = 3.00 s,

Instantaneous speed = \frac{dx}{dt}

Instantaneous speed(v) = 6t - 2\left \{ {{t=2} \atop {t=3}} \right.

Instantaneous speed,v(t=2 to t=3) = 18-2-12+2

Instantaneous speed, v = 6 \frac{m}{s}

c) the average acceleration between t = 2.00 s and t = 3.00 s

average acceleration = \frac{average velocity}{time}

average acceleration =  \frac{11.66}{3-2}

average acceleration = 11.66 \frac{m}{s^{2} }

d) the instantaneous acceleration at t = 2.00 s and t = 3.00 s

instantaneous acceleration = \frac{dv}{dt}

instantaneous acceleration =6

instantaneous acceleration = 6 \frac{m}{s^{2} }

e) for x =0

0 = 3.00t^{2} – 2.00t + 3.00

a = 3, b=-2, c=3

t= \frac{-b \pm \sqrt{b^{2} - 4ac} }{2a}

t= \frac{2 \pm \sqrt{4 - 36} }{6}

t= \frac{2 \pm \sqrt{-32} }{6}

general solution of this equation gives imaginary value. Hence, the given object is not at rest.

7 0
3 years ago
Read 2 more answers
A child on a swing falls a height of 1m. What speed will the child reach?
kirill [66]

Answer:v=4.42\ m/s

Explanation:

Given

Child falls a height of h=1\ m

Applying conservation of energy  we can write

Loss in Potential energy=Gain in kinetic energy

mgh=\frac{1}{2}mv^2

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 1}

v=\sqrt{19.6}

v=4.42\ m/s

Thus child reaches a velocity of 4.42 m/s

7 0
3 years ago
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