Answer:
<h3>The power of headlight in series connection is 29.64 W</h3>
Explanation:
Given :
Power of headlight
W
Power of starter
W
Voltage of headlight and starter
V
From equation of power,


For finding the resistance of headlight and starter,
⇒ For headlight,
Ω
⇒ For starter,
Ω
Since equivalent resistance,

Ω
So power in series is given by,

W
A=pi r^2
A=( 3.14159.......)(12.77)^2
A= 512.30m^2
V=d*t
Since d=75km=75000m
t=1.5h=3600*1.5= 5400s
=>V=75000*5400
=405000000m/s=4.05*10^8m/s
Answer:
percentage by volume of the solute = 45%
Explanation:
The percentage by volume of the solute in a solution is the percentage of the volume of the solute as against the overall volume of the solution.
In this example,
volume of solution = 300mL
volume of solute = 135mL
% volume of solute = (volume of solute ÷ volume of solution) × 100
= (135 ÷ 300) × 100
= 0.45 × 100 = 45%
∴ percentage by volume of the solute = 45%