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3 years ago

...5, _, 29, ..... The missing term is _

Mathematics

2 answers:

Svet_ta [14]3 years ago

7 0

Answer:

Step-by-step explanation:

see if you do the math you will find out that its 12 17+12=29

Alecsey [184]3 years ago

4 0

Answer:

Step-by-step explanation:

I think the answer is 17 if helpful please mark me brainliest!

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Please help mee pleaseee

nalin [4]

Answer:

The exact answer in terms of radicals is $x = 5*\sqrt[3]{25}$

The approximate answer is $x \approx 14.62009$ (accurate to 5 decimal places)

===============================================

Work Shown:

Let $y = \sqrt[5]{x^3}$

So the equation reduces to -7 = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since $y = \sqrt[5]{x^3}$ and y = 5, this means we can equate the two expressions and solve for x

$y = 5$

$\sqrt[5]{x^3} = 5$

$x^3 = 5^5$ Raise both sides to the 5th power

$x^3 = 3125$

$x = \sqrt[3]{3125}$ Apply cube root to both sides

$x = \sqrt[3]{125*25}$

$x = \sqrt[3]{125}*\sqrt[3]{25}$

$x = \sqrt[3]{5^3}*\sqrt[3]{25}$

$x = 5*\sqrt[3]{25}$

$x \approx 14.62009$

4 0

3 years ago

Read 2 more answers

Solve the following equation

Gnoma [55]

40x+8x^2=0 can be solved for x (there are two solutions):

Divide all 3 terms by the greatest common multiple (which is 8x):

40x+8x^2=0
------------- -----
8x 8x

5 + x = 0 produces the root x = - 5.

Setting 8x = 0 and solving for x produces the root x = 0.

Be certain to check these results. substitute x = -5 into 40x+8x^2=0. Is the resulting equation true or false? Next, subs. x=-5 into 40x+8x^2=0. Is the resulting equation true or false?

5 0

3 years ago

Read 2 more answers

You can upgrade lighting at your factory to LED bulbs that cost $6.95 each and last an average of 5 years. It costs S3 in labor

marshall27 [118]

Answer:

11.95 dollars

Step-by-step explanation:

Cost of one LED bulb = 6.95 dollars

Cost of changing one bulb = 3 dollars

Life of each bulb = 5 years.

In 10 years, only one time after 5 years the bulbs would have been changed