For this problem, the most accurate is to use combinations
Because the order in which it was selected in the components does not matter to us, we use combinations
Then the combinations are 
n represents the amount of things you can choose and choose r from them
You need the probability that the 3 selected components at least one are defective.
That is the same as:
(1 - probability that no component of the selection is defective).
The probability that none of the 3 selected components are defective is:

Where
is the number of ways to select 3 non-defective components from 117 non-defective components and
is the number of ways to select 3 components from 120.


So:

Finally, the probability that at least one of the selected components is defective is:

P = 7.4%
Answer:
The equation of the given circle is X²+y²+4x- 12y+15=0
Well 21 times 2 is 42 and 1/3 of 21 is 7 so 42+7 is 49. hope this is right
Answer:
$1,920
Step-by-step explanation:
you multiply 12 by 40. then, assuming a typical month is 4 weeks, you multiply that number by 4.
Answer:
D
Step-by-step explanation: