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3 years ago

Write first four terms of an AP when the first term is -2 and common difference is O.

Mathematics

2 answers:

Nina [5.8K]3 years ago

6 0

<h3>Answer: -2, -2, -2, -2</h3>

Explanation:

If the common difference is 0, then we're adding 0 to each term to get the next term. However, adding 0 doesn't change the number. So that's why we have the same thing written four times.

As another example, let's say the common difference was 1 instead of 0. That would mean the first four terms are -2, -1, 0, 1 since we add 1 to each term to get the next one (eg: -2+1 = -1).

vovikov84 [41]3 years ago

4 0

Answer:

-2, -2, -2, -2.

Step-by-step explanation:

If the common difference (d) is 0 then all terms are the same as the first:-

AP = a, a + d, a + 2d, a + 3d

Here we have -2, -2+0, -2 + 2(0), -2 + 3(0)

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3 years ago

Aya = a1 + (n - 1)d

Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

Step-by-step explanation:

Given

a₁ = -33

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An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = -33 and d = 4 in the nth term of the sequence

$a_n=-33+\left(n-1\right)4$

$\:a_n=-33+4n-4$

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Thus, the nth term of the sequence is:

$a_n=4n-37$

now substituting n = 26 in the nth term to determine the 26th term of the sequence

$a_n=4n-37$

$a_{26}=4\left(26\right)-37$

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$a_{26}=67$

Therefore, the 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

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3 years ago

Write first four terms of an AP when the first term is -2 and common difference is O.​

Write first four terms of an AP when the first term is -2 and common difference is O.