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aalyn [17]
3 years ago
5

A 4.7g sample of ethanol is burned in a calorimeter containing 95.8 mL of water. If the initial temperature of the water is 29.1

oC and the final temperature is 38.9oC, what is the energy per gram produced by the ethanol?
Chemistry
1 answer:
Anna11 [10]3 years ago
8 0

Answer:

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And out of reach

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Any time or place, no shame

You got my attention now

Can anybody ride my wave the same

You know what I'm talkin' about

Hit you with some truth

You're like a dream

I wanna believe

Hit you with some truth

When we're together

I can't even lie

You and me got chemistry

Got, got chemistry

Got chemistry

Feel it when you're close to me

And out of reach

And in between

We got la la la, lots of good vibrations

We got la la la, we got la la la

You and me got chemistry

Got, got chemistry

Got chemistry

You and me got, you and me got

You and me got chemistry, got, got chemistry,

Got chemistry

Feel it when you're close to me

And out of reach

And in between

Ohh we got chemistry

Feel it when you're close to me

And out of reach

And in between

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'Cause you and me got

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levacccp [35]

An ionization suppressor is an alkali metal capable of preventing ionization, which can be used in atomic spectroscopy to determine matter composition.

<h3>What is ionization?</h3>

Ionization refers to the phenomena capable of converting neutral atoms/molecules to electrically charged atoms/ions.

Ionization is a process by which radiation (e.g., alpha, beta, gamma rays) can pass energy to inert matter.

Some examples of ionization suppressors include salts of alkali metals (for example, potassium), which can be used in atomic spectroscopy to determine matter composition.

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4 0
3 years ago
Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10-26 kg. If you simplify and t
Talja [164]
<span>(a) what is the average volume (in cubic meters) required for each iron atom
For this case, the density of Iron would be </span>7.87g/cm³
<span>
V = 9.27 x 10^-26 kg / </span>7.87g/cm<span>³ ( 1 kg / 1000 g)
</span>V = 1.18 x 10-23 cm³<span>

(b) what is the distance (in meters) between the centers of adjacent atoms?
We assume the atoms as cube, so we use the volume of the cube to calculate the distance of the atoms.

V = </span>1.18 x 10-23 cm<span>³ = s</span>³
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