Answer:
C= 0.532M
Explanation:
The equation of reaction is
H2SO4 + 2KOH = K2SO4+ H2O
nA= 1, nB= 2, CA= ?, VA= 48.9ml, CB= 1.5M, VB= 34.7ml
Applying
CAVA/CBVB = nA/nB
(CA× 48.9)/(1.5×34.7)= 1/2
Simplify
CA= 0.532M
One would be phosporous whose configuration is 1s2 2s2 2p6 3s2 3p3
Answer:
Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure
Explanation:
The configuration of these elements is as follows;
Cl₁₇ = 2, 8,7 (the outer electron is 7)
Ca₂₀ = 2,8,8,2 (the outer electron is 2)
Ne₁₀ = 2,8 (the outer electron is 8)
Na₁₁ = 2,8,1 (the outer electron is 1)
Based on the outer electron value above, Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure.
Electronic configuration of cromium is
Cr-[Ar]4s¹3d⁵
When cromium loses two electrons it becomes Cr⁺².
So its electronic configuration becomes,
Cr⁺²-[Ar]3d⁴
One electron will go from 4s orbital and one electron will go from 3d orbital.
So the answer here is D. [Ar]3d⁴ -because after losing 2 electrons electronic configuration of cromium becomes [Ar] 3d⁴.
