moles NaOH = c · V = 0.2432 mmol/mL · 24.75 mL = 6.0192 mmol
moles H2SO4 = 6.0192 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.0096 mmol
Hence
[H2SO4]= n/V = 3.0096 mmol / 38.94 mL = 0.07729 M
The answer to this question is [H2SO4] = 0.07729 M
Answer:
It will a because it has a lower density than water
its a, c and e i think. the other guy who answered was incorrect so i dont really know the answer
Answer:
16974J of energy are required
Explanation:
The energy required is:
* The energy to heat solid water from -15°C to 0°C using:
q = m*S*ΔT
* The energy to convert the solid water to liquid water:
q = dH*m
* The energy required to increase the temperature of liquid water from 0°C to 75°C
q = m*S*ΔT
The first energy is:
q = m*S*ΔT
<em>m = Mass water = 25g</em>
<em>S is specific heat of ice = 2.03J/g°C</em>
<em>ΔT is change in temperature = 0°C - (-15°C) = 15°C</em>
q = 25g*2.03J/g°C*15°C
q = 761.3J
The second energy is:
q = dH*m
<em>m = Mass water = 25g</em>
<em>dH is heat of fusion of water = 80cal/g</em>
q = 80cal/g*25g
q = 2000cal * (4.184J/1cal) = 8368J
The third energy is:
q = m*S*ΔT
<em>m = Mass water = 25g</em>
<em>S is specific heat of water= 4.184J/g°C</em>
<em>ΔT is change in temperature = 75°C-0°C = 75°C</em>
q = 25g*4.184J/g°C*75°C
q = 7845J
The energy is: 7845J + 8368J + 761J =
16974J of energy are required
Answer:
0.068 g
Explanation:
The equation that is used to determine the fraction q remaining in water of volume V₁ after n extractions of volume V₂ is:
qⁿ = (V₁/(V₁ + KV₂))ⁿ
Substituting in the values gives the fraction of caffeine left in the water phase:
q³ = (4.0mL/(4.0mL + 4.6(2.0mL))³ = 0.0278
The fraction of caffeine extracted into the methylene chloride phase is:
1 - 0.0278 = 0.972
The amount of caffeine extracted into the methylene chloride is:
(0.070g)(0.972) = 0.068 g
