Molar mass of LiBr ( lithium bromide ) = <span>86.845 g/mol
</span><span>Amount of calculation to moles of lithium bromide (LiBr)
86.845 g ------------- 1 mole
100 g ----------------- ?
n = m / M
n = 100 / 86.845
n = 1.1514 moles of LiBr
V ---------------------1.1514 moles
1 L -------------------- 4 M
1.1514 * 1 / 4
V = 1151.4 / 4
V = 0,28785 L
hope this helps!
hope this helps !</span>
Energy were released from the walnut, q = 1,673.6 J
<h3>Equation :</h3>
To find the energy using formula,
q = mcΔt
where,
q is charge
m is mass
c is specific heat of water
Δt is change in temperature
So, given
t₁ = 50°C
t₂ = 60°C
m = 40g
c = 4.184 J/g
Now putting the values known,
We get,
q = mc(t₂ - t₁)
q = 40g x 4.184 J/g x (60 - 50)
q = 167.36 J x 10
q = 1,673.6 J
<h3>What is heat energy?</h3>
Heat is the thermal energy that is transferred when two systems with different surface temperatures come into contact. Heat is denoted by the letters q or Q and is measured in Joules.
To know more about specific heat :
brainly.com/question/11297584
#SPJ9
<h3>
<u>Answer</u> - 5.85g</h3>
<h3>
<u>Solution</u> - </h3>
Using the concentration equation, m = CVMo where m is the mass of solute, C is the concentration (M), V is the volume of solution (L) and Mo is molar mass of the solute (g):
Given,
Molar mass of NaCl, M = 58.5g/mol
Volume of the solution, V= 100ml = 0.1L
Molarity, S= 1M
Mass of the solute,W=?
W=SMV
= 1×58.5×0.1
= 5.85g
