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frutty [35]
3 years ago
15

Please help me with this anyone

Mathematics
1 answer:
katen-ka-za [31]3 years ago
6 0

Answer:

Step-by-step explanation:

Begin by combining like terms and then factoring. Combining like terms will give you

10p^2-17p-20=0 Using the "old-fashioned" way of factoring, the a times c method, our a = 10, b = -17 and c = -20.

a * c = 10(-20) = -200 and now we need the factors of 200 (don't worry about the negative) that combine to give us that middle term, -17p (here is where the negative matters). The factors of 200 are:

1. 200;  2, 100;  4. 50;  5, 40;  8, 25;  10, 20

The combination of those numbers that can be manipulated to give us a -17p is the 8, 25 as long as we say that the 25 is negative and the 8 is positive. Rewrite the original polynomial to reflect those factors:

10p^2-25p+8p-20=0 and then factor by grouping:

(10p^2-25p)+(8p-20)=0 and factor out from each set of parenthesis what is common:

5p(2p-5)+4(2p-5)=0 again factor out what is common:

(2p - 5)(5p+ 4) = 0. These are the factors; therefore the solutions are

2p - 5 = 0 so

2p = 5 and

p = 5/2  and

5p + 4 = 0 and

5p = -4 so

p = -4/5

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A clothing company sells slacks that are either blue or gray and pleated or non-pleated. Last month, the company sold 5 times as
qwelly [4]

Answer:

138 pairs

Step-by-step explanation:

The number of blue pleated slacks is 5 times the number of gray pleated slacks, so:

blue\ pleated = 5 * gray\ pleated (eq1)

The number of gray non-pleated is twice the number of blue non-pleated slacks, so:

blue\ nonpleated = 2 * gray\ nonpleated (eq2)

The total number of blue slacks is 333, and the total number of gray slacks is 225, so we have that:

blue\ pleated + blue\ nonpleated = 333 (eq3)

gray\ pleated + gray\ nonpleated = 225 (eq4)

If we add (eq1) and (eq2), we have:

blue\ pleated + blue\ nonpleated = 5*gray\ pleated + 2*gray\ nonpleated (eq5)

Using (eq3) and (eq4) in (eq5), we have:

333 = 2*225 + 3*gray\ pleated

gray\ pleated = 117/3 = 39

From (eq1), we have:

blue\ pleated = 5*39 = 195

From (eq3), we have:

blue\ nonpleated = 333 - 195 = 138

3 0
3 years ago
Solve 13+x/2=3x for x
skad [1K]
13=3x-x/2 13=5x/2 26=5x X=5.2
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A high school band asked a number of students whether they would like blue, gold, or both for the uniforms for the band. The res
Anna35 [415]
Given a Venn diagram showing the number of students that like blue uniform only as 32, the number of students that like gold uniform only as 25, the number of students that like blue and gold uniforms as 12 and the number of students that like neither blue nor gold uniform as 6.

Thus, the total number of students interviewed is 75.

Recall that relative frequency of an event is the outcome of the event divided by the total possible outcome of the experiment.

From the relative frequency table, a represent the relative frequency of the students that like gold but not blue.
From the Venn, diagram, the number of students that like gold uniform only as 25, thus the relative frequency of the students that like gold but not blue is given by
\frac{25}{75} = \frac{1}{3}=0.33=33\%

Therefore, a = 33% to the nearest percent.

Similarly, from the relative frequency table, b represent the relative frequency of the students that like blue but not gold.
From the Venn, diagram, the number of students that like blue uniform only as 32, thus the relative frequency of the students that like gold but not blue is given by
\frac{32}{75} = 0.427=42.7\%

Therefore, b = 43% to the nearest percent.
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3 years ago
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NemiM [27]
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Is each line parallel, perpendicular, or neither parallel nor perpendicular to a line whose slope is -6?
babymother [125]

Answer:

Line M - neither

Line N - parallel

Line P - perpendicular

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Step-by-step explanation:

If a line is perpendicular to another, the slope will be the opposite, e.g. -6, opposite slope, -6.

If a line is parallel to another, the slope will be the exact same, e.g. -6, same slope, 1/6.

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