For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}
6
1
.
Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).
Using the rule of product, this is:
\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}
6
1
×
6
1
=
36
1
.
$154.63
Year 1: $25
Year 2: $27.5
Year 3: $30.25
Year 4: $33.28
Year 5: $36.60
Answer: John is most likely to win.
Step-by-step explanation: John is most likely to win because he can roll the following numbers:
2,6
3,5
4,4
5,3
6,2
Oh Neil Can only roll these numbers
5,6
6,5
So John would most Likely win
Any value which is more than 2 standard deviations away from the mean is considered to be "unusual."
2 standard deviations above the mean 52.4 mp would be 52.4+2(1.8), or 56; 2 std devs below the mean would be 52.4 - 2(1.8), or 48.8. Thus, any value larger than 56 or any value smaller than 48.8 would be "unusual."
54.8, 49.1 and 51.3 are not unusual; 56.5 is unusual, because it's greaster than 56.
