3 years ago

A horse is running on a circular path with constant speed but its direction is changing at every point. It is

Physics

1 answer:

chubhunter [2.5K]3 years ago

7 0

Answer:

accelerating.

Explanation:

A horse is running on a circular path with constant speed but its direction is changing at every point. Thus, it is accelerating.

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marishachu [46]

Answer: B

Explanation:

4 0

3 years ago

What happens in earth's interior to produce a magnetic field describe the layer where the magnetic field is produced?

Lisa [10]

Answer:

The rotation of Earth on its axis causes electric currents to form a magnetic field which extends around the plane

Explanation:

On Earth, flowing of liquid metal in the outer core of the planet generates electric currents.

8 0

4 years ago

A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, wha

Alborosie

Answer:

$v = 70.95 \ m/s.$

Explanation:

Given data:

Mass of the man, $m = 59 \ kg$

Total mechanical energy, $E_{i} = 150,023 \ \rm J$

Height, $h = 2.6 \ m$

Suppose there is no external force acting on the man. In this situation, the total mechanical energy (kinetic + potential) will remain steady.

Let the speed of the man at 2.6 m be <em>v</em>.

Thus,

$E_{i} = E_{f}$

$E_{i} = \frac{1}{2}mv^{2} + mgh$

$150023 = 0.5 \times 59 \times v^{2} + 59 \times 9.80 \times 2.6$

$\Rightarrow \ v = 70.95 \ m/s.$

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3 years ago

If 400 pa of pressure is applied to an area of 55 m2, which is the resulting force?345 n7.27 n22,000 n

VashaNatasha [74]

The answer should hopefully be: 7.27N

7 0

4 years ago

Read 2 more answers

From Gauss's law, the electric field set up by a uniform line of charge is given by the following expression where is a unit vec

Evgesh-ka [11]

Answer:

$\Delta V=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})$

Explanation:

Using the Gauss Law, we obtain the electric Field for a uniform large line of charge:

$2\pi r L*E=\lambda *L/\epsilon_{o}$

$E=\lambda /\(2 \pi* r *\epsilon_{o})$

We calculate the potential difference from the electric field:

$\Delta V=-\int\limits^{r_{1}}_{r_{2}} E \, dr =-\int\limits^{r_{1}}_{r_{2}} \lambda dr/ (2\pi*r*\epsilon_{o})=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})$

5 0

4 years ago