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WITCHER [35]
3 years ago
6

An object moving at 34m/s takes 3s to come to a stop. What is the object’s acceleration?_____m/s2

Physics
2 answers:
nikklg [1K]3 years ago
7 0
Acceleration = change in velocity / time
A=(vf -vi)/t
Vf=0
Vi=34
T=3
A=(0-34)/3 = -11.33 ms^2
Remember that acceleration is negative since it's slowing down so it's accelerating in the opposite direction than it was initially going.
ipn [44]3 years ago
3 0
Deceleration = vel change / time = 34/3 = 11.33 m/s^2

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How do i figure out this question?
nikklg [1K]

Answer:

0.75 g/cm^3

Explanation:

The formula for density:

\rho = \frac{m}{V}

Where m is the mass and V is the volume.

So, we can substitute values for m and V:

\rho = \frac{277}{370}\approx0.75

Therefore, the density is 0.75 g/cm^3 (watch the units!)

8 0
3 years ago
Read 2 more answers
Consider two uniform solid spheres where both have the same diameter, but one has twice the mass of the other. how much larger i
egoroff_w [7]
<span>The moment of inertia of the large sphere will be twice that of the smaller sphere.
   The formula for the moment of inertia for a solid sphere is:
 I = (2/5)mr^2
 where
 I = moment of inertia
 m = mass
  r = radius

   Since both spheres have the same diameter, they also have the same radius, so the only change is their mass. And the moment of inertia is directly proportional to their mass as shown by the above formula. So the sphere with twice the mass will have twice the moment of inertia, or 2 times.</span>
5 0
3 years ago
How much force is needed to accelerate a 68 kilogram-skier at a rate of 1.2 m/sec^2?
DiKsa [7]
<span>Answer: Force = 81.6 N

Explanation:
According to Newton's Second law:
F = ma --- (1)

Where F = Force = ?
m = Mass = 68 kg
a = Acceleration = 1.2 m/s^2

Plug in the values in (1):
(1) => F = 68 * 1.2
F = 81.6 N (The force needed to accelerate the skier at a rate of 1.2 m/s^2)</span>
4 0
3 years ago
Read 2 more answers
What is the weight of a 8-kg substance in N, kN, kg·m/s2, kgf, lbm·ft/s2, and lbf?
kvv77 [185]

Answer:

W = 78.48N\\W =0.0784kN\\W = 8kgf\\

W= 3.6lbf\\W= 115.2 lbm*ft/s2

Explanation:

if

m=8kg=3.6lb\\

and g=9.81 m/s2=32.16 ft/s2

and

W=m*g

we can just replace de mass and gravity and we have

W = 8kg * 9.81 \frac{m}{s^{2} } =78.48N\\W = \frac{78.48N}{1000} =0.0784kN\\W = 8kgf\\

W= 3.6lbf\\W= 3.6lbm *32.16 ft/s2 =115.2 lbm*ft/s2

5 0
4 years ago
A gray kangaroo can bound across level ground with each jump carrying it 9.6 m from the takeoff point. Typically the kangaroo le
xz_007 [3.2K]

Answer:

(A) 11 m/s

(B) 1.3 m

Explanation:

Horizontal range, R = 9.6 m

Angle of projection, theta = 28 degree

(A)

Use the formula of horizontal range

R = u^2 Sin 2 theta / g

u^2 = R g / Sin 2 theta

u^2 = 9.6 × 9.8 / Sin ( 2 × 28)

u = 10.65 m/s

u = 11 m/s

(B)

Use the formula for maximum height

H = u^2 Sin ^2 theta / 2g

H =

10.65 × 10.65 × Sin^2 (28) / ( 2 × 9.8)

H = 1.275 m

H = 1 .3 m

4 0
3 years ago
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