Ask question

Ask question

All categories

3 years ago

9

What type of lens is this?

2 answers:

julia-pushkina [17]3 years ago

6 0

The lens type is concave

slavikrds [6]3 years ago

6 0

Tip: A convex lens is thicker at the centre than at the edges.

When light goes through a concave lens, the light that goes through that lens spreads out more due to the structure of the surface of the lens. A concave lens does not form a focal point at the opposing side of the lens. Instead, it spreads out, doing the exact opposite of what a convex lens does. In the picture, we see a lens where the light goes through and unifies at the opposing side, which is what a convex lens does. So, the lens in that image is a convex lens.

3. What type of lens is this?

<u>Answer: Convex</u>

Wrong Answer: Concave

You might be interested in

Four particles are in a 2-d plane with masses, x- and y- positions, and x- and y- velocities as given in the table below: what i

Arte-miy333 [17]

I attached the picture of the missing table.
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
$R=\frac{1}{M}\sum_{i=1}^{n=i}m_ir_i$
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
$R_x=\frac{1}{M}\sum_{i=1}^{n=i}m_ix_i$
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
$R_x=0.96m$
Part 2
To calculate the y coordinate of the center of mass we will use this formula:
$R_y=\frac{1}{M}\sum_{i=1}^{n=i}m_iy_i$
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
$R_y=-0.84m$
Part 3
We will calculate speed along x and y-axis separately and then will add them together.
$v_x=\frac{\sum_{i=1}^{n=i}m_iv_x_i}{M}$
$v_y=\frac{\sum_{i=1}^{n=i}m_iv_y_i}{M}$
Total velocity is:
$v=\sqrt{v_x^2+v_y^2}$
Once we calculate velocities we get:
$v_x=-1.08\frac{m}{s}\\ v_y=-0.03\frac{m}{s}\\ v=\sqrt{(-1.08)^2+(-0.03)^2}=1.08\frac{m}{s}$
Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing

3 0

3 years ago

In a ballistics test, a 52g bullet hits a sand bag and stops after moving 1.34 m. If the initial bullat

olya-2409 [2.1K]

Answer:

Friction force on the bullet is 58.7 N opposite to its velocity

Explanation:

As we know that initial speed of the bullet is 55 m/s

after travelling into the sand bag by distance d = 1.34 m it comes to rest

so final speed

$v_f = 0$

now we can use kinematics top find the acceleration of the bullet

$v_f^2 - v_i^2 = 2 a d$

so we have

$0 - 55^2 = 2(a)(1.34)$

$a = -1128.7 m/s^2$

now by Newton's II law we know that

$F = ma$

so we have

$F = (0.052)(-1128.7)$

$F = -58.7 N$

8 0

4 years ago

Boyle’s Law: When____ is held constant, the pressure and volume of a gas are___ proportional.

Aleksandr-060686 [28]

Answer:

When temperature is held constant, the pressure and volume of a gas are not proportional.

Explanation:

That is Boyle's Law

7 0

3 years ago

A beam of electrons is accelerated from rest through a potential difference of 0.400 kV and then passes through a thin slit. Whe

Oksi-84 [34.3K]

Answer:

v= 103.5 V; energy =1.65 x 10^-17

Explanation:

the deflected energy eV sin θ

8 0

3 years ago

Read 2 more answers

PLEASE HELP, NO ONE IS HELPING MEEEE :(

Blizzard [7]

Answer:

probably the trip where it took u 5 seconds

4 0

3 years ago

Read 2 more answers