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Alisiya [41]
3 years ago
8

Simplify:

%5B3%5D%7By%5E4%7D%5Cright%29%7D%7B12x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Ccdot%20%5Csqrt%5B4%5D%7Bx%5E3%7D%7D" id="TexFormula1" title="\frac{\left(x^{\frac{5}{2}}\cdot 6y^2\cdot \sqrt[3]{y^4}\right)}{12x^{\frac{1}{2}}\cdot \sqrt[4]{x^3}}" alt="\frac{\left(x^{\frac{5}{2}}\cdot 6y^2\cdot \sqrt[3]{y^4}\right)}{12x^{\frac{1}{2}}\cdot \sqrt[4]{x^3}}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Anestetic [448]3 years ago
7 0

Answer:

  • \frac{1}{2} x^{\frac{5}{4} }y^{\frac{10}{3}}

Step-by-step explanation:

  • \frac{x^{\frac{5}{2} }*6y^2*\sqrt[3]{y^4}  }{12x^{\frac{1}{2}}*\sqrt[4]{x^3} } =
  • \frac{x^{ \frac{5}{2} }6y^2y^{ \frac{4}{3} }  }{12x^{ \frac{1}{2} }x^{ \frac{3}{4} }} =
  • \frac{1}{2} x^{\frac{5}{2}  - \frac{1}{2} - \frac{3}{4}}y^{2+\frac{4}{3}}=
  • \frac{1}{2} x^{\frac{5}{4} }y^{\frac{10}{3}}
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