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3 years ago

Help me ASAP please.

Mathematics

1 answer:

Leni [432]3 years ago

4 0

Answer:

Step-by-step explanation:

The vertex will occur when t=-b/(2a) for the quadratic ax^2+bx+c

In this case

t=-200/(2(-16))

t=-200/-32

t=6.25

g(6.25)=-16(6.25^2)+200(6.25)

g(6.25)=625ft

So the maximum height of the rocket is 625 feet and it reaches this height at 6.25 seconds.

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Name the property the equation illustrates. 8 + 5.3 = 5.3 + 8

VMariaS [17]

The answer to the question is letter "D. Commutative Property of Addition". The property states that if there are two numbers which we may represent by a and b, the value of a + b is equal to the value of b + a. The given, 8 + 5.3 = 5.3 + 8 is an example of this property.

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2 years ago

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A quadrilateral WXYZ contains wxy where measure of wxy=92 degrees. Once rotated 270° about the origin and translated 2 units up,

Marianna [84]

Answer:

C. 92 degrees

Step-by-step explanation:

Given that the $\angle{wxy}=$ 92° which is one of the angles of the quadrilateral WXYZ

The quadrilateral is first rotated by 270° about the origin and then translated 2 units up, the new position of the quadrilateral is W'X'Y'Z'.

The shape of the quadrilateral is remained unchanged due to rotation and translation, so all the angles of the final quadrilateral W'X'Y'Z' is the same as the angles of the given quadrilateral WXYZ.

So, $\angle{w'x'y'}= \angle{wxy}$

By using the given value,

$\angle{w'x'y'}=$ 92°

Hence, option (C) is correct.

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2 years ago

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Answer:

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Step-by-step explanation:

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Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$