Answer:
(0, 2) and (2, 5) are solutions to the function.
Step-by-step explanation:
Given the following linear function:
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"f(x)" is a function notation.
"f" represents the function name. In function notations, you can use any letter to represent a function name. However, "f" is commonly used to express function notations.
"x" is your input variable. This is the x-values that you substitute into the function to get an output, or y-value.
f(x) is your output value.
We are also given the following points: (0, 2) and (2, 5).
In order to determine whether these points work with the given function, simply substitute their values into the function.
<h3>(0, 2) where x = 0, y = 2:</h3>
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⇒ The function notation, "f(0)" simply means the <em>function of zero</em>, which corresponds to the input value of zero (0).
Next, substitute the value of y = 2 into the function as an output value:

2 = 0 + 2
2 = 2 (True statement). This means that the point, (0, 2), is a solution to the given function. The point (0, 2) represent the given function's <u>y-intercept</u>, which is the point on the graph where it crosses the y-axis. The y-coordinate of 2 is the value of <em>b</em> in the <u>slope-intercept form</u>, y = mx + b.
<h3>(2, 5) where x = 2, y = 5:</h3>
We will do the same process for (2, 5):
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
Substitute the value of y = 5 into the function as an output value:

5 = 3 + 2
5 = 5 (True statement). This means that the point, (2, 5), is also a solution to the given function.