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Juliette [100K]
3 years ago
5

Amber built a large rectangular garden that is 9 meters long and had an area of 72 square meters, what is the perimeter of amber

's garden?
Mathematics
1 answer:
drek231 [11]3 years ago
7 0
So we know that the length of the rectangle is 9 meters.

In order to find area of a rectangle, you multiply the length by the width.

To find the width, you divide the area by the side you do have , which is 9 meters.

72 divided by 9 is 8.

So the width 8 meters, and now to find the perimeter you must add all sides of the rectangle.

9+9+8+8 = 34.

The perimeter of the rectangular garden is 34 meters.
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Please helpppppppp:(((((((((((((((((((
Alja [10]

Answer:

The area is 243 square feet

Step-by-step explanation:

The perimeter of a rectangle is the sum of all four sides.

Two of the sides represent the length and two represent the width.

Given what we know and using l to represent the length and w to represent the width.

l + l + w + w = 72ft

or more concisely

2l + 2w = 72ft

The four sides all add together to equal 72ft

We also know that

l = 3w

This says the length is equal to 3 times the width

we have two unknowns, l and w, and now we have two related equations so we can solve for l and w.

The first thing we will do is replace l with 3w in the first equation because the second equation tells us that l is the same as 3w. Making the replacement gives us

2(3w) + 2w = 72ft

2 times 3w is 6w

6w + 2w = 72ft

6w plus 2w is 8w

8w = 72ft

Now if we divide both sides by 8 we maintain the equality since we are making the same change to both sides

8w / 8 = 72ft / 8

8w divided by 8 is 1w or just w and 72ft divided by 8 is 9ft

w = 9ft

So now we know the width is 9ft

if we now replace w with 9 in one of our original equations we can solve for l, let's use l = 3w

l = 3(9ft)

3 times 9 is 27 so

l = 27ft

So the length is 27ft which is 3 times the width of 9ft

The area of a rectangle is length times width or l x w, so

area = 27ft x 9ft

area = 243sqft

ft means feet and sqft means square feet

4 0
3 years ago
Help me with this lol value of( 2^3)^2
ss7ja [257]

Answer:

64

Step-by-step explanation:

first, we'll start with the value inside the parenthesis, which is 2³

2³ means to multiply 2 by itself 3 times

so it would be

2×2×2=8

which then means that the expression is now (8)²

now we need to do (8)², which is to multiply 8 by itself twice

8*8=64

hope this helps!

6 0
3 years ago
Help, Perhaps? this one has me kinda stumped, i know its prob easy, im just not to big brain rn lol :Sweat_emoji:
Naddika [18.5K]

Answer:

Step-by-step explanation:

g

4 0
3 years ago
Read 2 more answers
GET BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION!
Tresset [83]

Interpreting the inequality, it is found that the correct option is given by F.

------------------

  • The first equation is of the line.
  • The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.

In standard form, the equation of the line is:

x + 2y = 6

2y = 6 - x

y = -0.5x + 2

Thus it is a decreasing line, which removes options J.

  • We are interested in the region on the plane below the line, that is, less than the line, which removes option H.

------------------

  • As for the second equation, the normalized equation is:

3x^2 + 3y^2 = 12

3(x^2 + y^2) = 12

x^2 + y^2 = 4

  • Thus, a circle centered at the origin and with radius 2.
  • Now, we have to check if the line x + 2y - 6 = 0, with coefficients a = 1, b = 2, c = -6, intersects the circle, of centre x = 0, y = 0
  • First, we find the following distance:

d = \sqrt{\frac{|ax + by + c|}{a^2 + b^2}}

  • Considering the coefficients of the line and the center of the circle.

d = \sqrt{\frac{|1(0) + 2(0) - 6|}{1^2 + 2^2}} = \sqrt{\frac{6}{5}} = 1.1

  • This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.

A similar problem is given at brainly.com/question/16505684

3 0
3 years ago
Graph the equation: x = y^2 - 2
Lesechka [4]
Draw a cartesian plane, create a graph with the equation x = y^2 - 2
then substitute numbers into the equation so that it is true, to find points on the graph, e.g. substitute y with 1, you get 
x = 1^2 - 2
x = 1 - 2 = -1, so when y = 1, x = -1, this point is (-1, 1)

for the next substitute y with 2,
x = 2^2 - 2
x = 4 - 2 = 2, the point is (2, 2)
you might want to try negative values of y 
y = -1, x = (-1)^2 - 2
x = -1 the point is (-1,-1)

then plot the points on the graph
5 0
3 years ago
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