Let 3<em>n</em> + 1 denote the "number" in question. The claim is that
(3<em>n</em> + 1)² = 3<em>m</em> + 1
for some integer <em>m</em>.
Now,
(3<em>n</em> + 1)² = (3<em>n</em>)² + 2 (3<em>n</em>) + 1²
… = 9<em>n</em>² + 6<em>n</em> + 1
… = 3<em>n</em> (3<em>n</em> + 2) + 1
… = 3<em>m</em> + 1
where we take <em>m</em> = <em>n</em> (3<em>n</em> + 2).
Answer:
36 dollars
Step-by-step explanation:
We need to think backwards to solve this question.
(8 - 2) x 2 = 12
(12 - 2) x 2 = 20
(20 - 2) x 2 = 36
Answer:
1140
Step-by-step explanation:
52/x=20/100
52(20)=100(x)
52(20) = 1040
100(x) = 100
1040+100= 1140
Https://www.khanacademy.org/math/in-sixth-grade-math/ratio-and-proportion/unitary-method/v/finding-unit-rates
C. 9^4
when dividing with exponents, i usually just look at the exponents and subract them so i did 12-8 for this problem