Solution :
Faulty electrical connects = P(A) = 0.80
Mechanical defects = P(B) = 0.92
Mechanical defects are related to loose keys = P(C/B) = 0.27
Improper assembly = P(D/B) = 0.73
Defective wires = P(E/A) = 0.35
Improper connections = P(F/A) = 0.13
Poorly welded wires = P(G/A) = 0.52
Now, the probability due to loose keys = 0.27 x 0.92 = 0.2484
Improperly connected = 0.13 x 0.80 = 0.1040
Poorly welded wires = 0.52 x 0.80 = 0.4160
So, the probability that a failure is due to improperly connected or poorly welded wires = 0.1040 + 0.4160
= 0.5200
Answer:
Number of Possible Sequence = 5 x 4 x 3 x 2 x 1 = 120 ways
Please give 5-star rating
C and D.If I'm right,can u make me the brainliest answer?Thank You.
Answer:
UR MOM
Step-by-step explanation:
STIL YOUR MOM
Hello!
To find the side length you use the equation
a is side length
d is diagonal
Put in the number we know
Divide
Multiply
a = 19.091
The answer is 19.09
Hope this helps!
