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3 years ago

A school had 600 students, 25% were 6th graders, 35% were 7th graders the rest were 8th graders.

Mathematics

1 answer:

Natalija [7]3 years ago

5 0

Answer:

240

Step-by-step explanation:

25% of 600: 150

35% of 600: 210

210+150= 360

600-360 = 240

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A circle has a CIRCUMFERENCE of 6. What is it's DIAMETER? thank you!

kati45 [8]

C = pi * d
d = C / pi
d = 6 / 3.14
d = 1.91 units

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3 years ago

Which best describes the transformation from the graph of f(x) = x2 to the graph of

RoseWind [281]

Transformations

(x-3)...: That means the graph shifted 3 units right.

...-1: that means the graph shifted 1 unit down.

answer: 3 units right, and 1 down

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3 years ago

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The equation h = 0.019s

TEA [102]

Answer:

s = 28.09 m/s

Step-by-step explanation:

Given that,

The equation that gives the height of the largest ocean waves when the wind speed is s knots is given by :

$h=0.019s^2$

We need to find the wind speed if the largest waves are 15 feet high.

Put h = 15 feet in the above equation as follows :

$15=0.019s^2\\\\s^2=\dfrac{15}{0.019}\\\\s=28.09\ m/s$

So, the speed of the wind is 28.09 m/s.

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3 years ago

What 5 numbers that round down to 600

8090 [49]

*It depends what place value needs to be rounded down, but without any specific place values, here are my answers*

600.1

601

600.44

602.1

644.4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

-Hope this helps :)

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4 years ago

100 POINTS AND BRAINLIEST

zysi [14]

Answer:

8 square units and $\frac{40}{3}$ square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor $\frac{1}{3},$ then

$\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.$

2. Triangles ABC and DBE are similar with scale factor $\frac{2}{3},$ then

$\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.$

3. Thus, the area of the quadrilateral DFGE is

$A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.$

and the area of the quadrilateral ADEC is

$A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.$

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3 years ago

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