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puteri [66]
3 years ago
5

What is the range for the following set of measurements?

Mathematics
1 answer:
Elden [556K]3 years ago
8 0

Answer:

20

Step-by-step explanation:

The range is the largest number take away the smallest

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alexdok [17]

Answer:

18

Step-by-step explanation:

3 0
2 years ago
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4. Jan bought donuts for $6.75. Each bagel cost<br> $0.75. How many bagels did she buy?
Nataly_w [17]

Answer:

9 bagels

Step-by-step explanation:

Divide the price ($6.75) by the price of one bagel ($0.75) to get the amount of bagels Jan bought. (9)

6 0
3 years ago
Ned has 55 marbles in his collection he has twice as many white marbles as red marbles he has five more blue marbles than white
nika2105 [10]

Answer:

7 marble's

Step-by-step explanation:

55 marbles and twice as many white marbles as red marbles and he has 5 more blue marbles than white marble's

4 0
3 years ago
You are selling a mobile app for $10 per user per month.if you get 7 users every month starting with 10 in the first month.how m
Ahat [919]

Selling price of app per user = $10 per month

Total no. of user in first month = 10

To tal no. of user added per month = 7

We have to find how much money is earned in one year

So the formula is n/2 * (2a +(n-1)d)

Here we have n = 12 which is total no. of months

a = 100 , which is money earned in one month

d = 70 , which is increase in money earned per month

So money earned in a year comes out to be 5820

4 0
3 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
Afina-wow [57]

Answer:

\large \boxed{\textbf{30.54 yr}}

Step-by-step explanation:

For species A,

P =2000e^{0.05t}

For species B,

P =5000e^{0.02t}

When their populations are equal,

\begin{array}{rcl}2000e^{0.05t} & = & 5000e^{0.02t}\\e^{0.05t} & = & 2.5e^{0.02t}\\0.05t & = & \ln2.5 + 0.02t\\0.05t & = & 0.9163 + 0.02t\\0.03t & = & 0.9163\\t& = & \dfrac{0.9163}{0.03}\\\\& = & \mathbf{30.54}\\\end{array}\\\text{The populations of species A and B will be the same in $\large \boxed{\textbf{30.54 yr}}$}

The diagram below shows the population of Species A overtaking that of Species B in about 30.5 yr.

3 0
3 years ago
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