Consider such events:
A - slip with number 3 is chosen;
B - the sum of numbers is 4.
You have to count 
Use formula for conditional probability:
1. The event 
consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event is
2. The event 
consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event is
3. Then
Answer: 
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Solving in steps</u>
- 1. ⇒ z + (-0.72) - (-0.72) = -2.5 - (-0.72)
- 2. ⇒ z = - (2.5 - 0.72)
- 3. ⇒ z = - 1.78
The student's mistake was adding (-0.72) instead of - (-0.72) or 0.72
That's about as much as you can simplify this problem.
I hope this helps! :)
Answer:
I think it's Bike 1, so sorry if I'm wrong
Step-by-step explanation:
