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3 years ago

What is the slope of the line through (1, 9) and (–3, 16)?

Mathematics

1 answer:

Lerok [7]3 years ago

3 0

Answer:

Step-by-step explanation:

slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

= $\frac{16-9}{-3-1}$

= $\frac{7}{-4}$

Therefore slope = -7/4

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What is the value of this expression? (−4)4

Marina86 [1]

Answer:

-16

Step-by-step explanation:

Anything written in the form of a(b) or (b)a means a × b:

(-4)4 means -4 × 4 which is -16 (a positive and a negative multiplied together make a negative).

Hope this helps!

8 0

2 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

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2 years ago

What was two. thirds and fifth twelve

Harrizon [31]

The answer is 1 and 1/12 because you have to have a common denomonator.

4 0

3 years ago

Need help on this question thank you

Ivahew [28]

Answer:

Step-by-step explanation:

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3 years ago

Do what it says on the image (NO SPAM LINKS!!)

Gennadij [26K]

Answer:

The answer is B.

Step-by-step explanation:

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6 0

1 year ago