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Lunna [17]
3 years ago
6

Answer as fast as you can

Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

better picture?

Step-by-step explanation:

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What’s the correct answer for this question?
erik [133]

Answer:

B:

Step-by-step explanation:

Measure of ARC AFB is 180°

Why?

This is because AB is a diameter.

4 0
3 years ago
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What operation should be performed SECOND to solve this problem?
Molodets [167]
Answer
<span>B multiplication

hope it helps</span>
4 0
3 years ago
What is the difference between 3/7 and 1/14 ?
mars1129 [50]

It would be: 3/7-1/14 = 6-1 / 14 = 5/14

So, 5/14 is your answer..........

8 0
3 years ago
Solve the system substitution y= 4x + 1 and 3x+2y =13
strojnjashka [21]

Given :

{\qquad \sf \dashrightarrow  y= 4x + 1 \: –––– \sf \:  (i)}

{\qquad \sf \dashrightarrow   3x + 2y = 13 \: –––– \sf \:  (ii)}

Now, Substituing the value of y in equation (ii) :

{\qquad \sf \dashrightarrow   \: 3x + 2y = 13   }

{\qquad \sf \dashrightarrow   \: 3x + 2(4x + 1) = 13   }

{\qquad \sf \dashrightarrow   \: 3x + 8x + 2 = 13   }

{\qquad \sf \dashrightarrow   \: 11x + 2 = 13   }

{\qquad \sf \dashrightarrow   \: 11x  = 13 - 2   }

{\qquad \sf \dashrightarrow   \: 11x  = 11   }

{\qquad \sf \dashrightarrow   \: x  =  \dfrac{11}{11}    }

{\qquad \sf \dashrightarrow   \bf \: x  = 1   }

Now, substituting the value of x in equation (i) :

{\qquad \sf \dashrightarrow  y= 4x + 1}

{\qquad \sf \dashrightarrow  y= 4(1) + 1}

{\qquad \sf \dashrightarrow  y= 4 + 1}

{\qquad \bf \dashrightarrow  y= 5}

8 0
2 years ago
Graph the image of the given triangle under a dilation with a scale factor of −2 and center of dilation (0, 0) .
Ronch [10]

To dilate an object means to enlarge or reduce the size of the object. The scale factor will determine how much larger or smaller the object will become.  If this factor is greater than 1, the object will increase in size. Otherwise, if the factor is less than 1, the object will decrease in size. So, the dilated object will be similar to its original. On the other hand, when corresponding points of the original and dilated figures are connected by straight lines, the center of dilation is the point where all the lines meet. In this problem, the center is (0, 0). When the center is the origin we need to multiply all the original coordinates of the object by the scale factor given. So:


A(-4, 1) \rightarrow A'=-2(-4,1) \rightarrow A'(8,-2) \\ \\ B(-3, -4) \rightarrow B'=-2(-3,-4) \rightarrow B'(6,8) \\ \\ C(-2, -2) \rightarrow C'=-2(-2,-2) \rightarrow C'(4,4)


So, the graph of the dilated triangle is shown in the Figure below

8 0
3 years ago
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