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3 years ago

How is the quadritael ABCD not a rhombus nor rectangle? I already prove it is a parallelogram

Mathematics

1 answer:

Firdavs [7]3 years ago

5 0

Answer:

fix your graph first .to be able to solve it check your point.

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A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib

Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 502, \sigma = 115$

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{590 - 502}{115}$

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 502}{115}$

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

6 0

2 years ago

Write y = 2x2 + 4 in function notation.

aleksandr82 [10.1K]

Answer:

0,4

Step-by-step explanation:

4 0

3 years ago

6 freshmen, 9 sophomores, 8 juniors, and 10 seniors are eligible to be on a committee. If a committee of 14 students is chosen a

denpristay [2]

<h3>Answer: 0.027145</h3>

=========================================

Work Shown:

You will be using the nCr combination formula here. Refer to the attached image below (figures 1 through 5).

We have a pool of n = 6 freshmen and we're selecting r = 2 individuals from this pool, so there are nCr = 6C2 = 15 ways to pick the two freshmen (see figure 1).

There are 84 ways to pick the sophomores since 9 C 3 = 84 (see figure 2)

Refer to figure 3 to see how 8 C 4 = 70. So there are 70 ways to pick the juniors.

Refer to figure 4 to see how 10 C 5 = 252. There are 252 ways to pick the seniors.

Finally, refer to figure 5 to see how 33 C 14 = 818,809,200. This is the number of ways to pick 14 students from a pool of 33 (add up all the students).

--------------

Multiply out the results of figures 1 through 4 to get:

15*84*70*252 = 22,226,400

This represents the number of ways to select all the students as mentioned in the instructions.

Then divide this over the result of figure 5

(22,226,400)/(818,809,200) = 0.02714478537858

This rounds to 0.027145 when rounding to 6 decimal places.

8 0

4 years ago

Perform the indicated operation.

Elodia [21]

Answer:

Step-by-step explanation:

g(-x) = x+4, h(g(-x))=h(x+4)=(x+4)^2+3(x+4)=x^2+11x+28

7 0

3 years ago

How do I solve 18=6(2x-8)

lorasvet [3.4K]

Answer:

x= 5.5

Step-by-step explanation:

18=12x-48

-12x= -48-18

-12x= -66

x= -66/-12

x= 5.5

4 0

4 years ago

Read 2 more answers

How is the quadritael ABCD not a rhombus nor rectangle? I already prove it is a parallelogram​

How is the quadritael ABCD not a rhombus nor rectangle? I already prove it is a parallelogram