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Sergio039 [100]
4 years ago
12

What is the mixed number for 62.8

Mathematics
2 answers:
grandymaker [24]4 years ago
8 0
62 8/10 is the answer.
 .8 =8/10
UkoKoshka [18]4 years ago
4 0
62 8/10 I believe  this is the answer.
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WILL GIVE FULL 34 POINTS! Find the domain of the composite function f*g if f(x) = x/(x+3) and g(x) = 2/x
andrew-mc [135]
(f*g)(x)=2/x /2/x+3
2/x / (2+3x)/x =
2/x *. x/(2+3x) =
2x / x(2+3x)

undefined when denominator is 0 or when x=0 or x=-2/3. the domain is all real numbers except these 2
3 0
3 years ago
Rewrite the equation below in standard form.
eduard
Rewrite the equation below in standard form.
-3x+6y=12


C. -x+2y=4

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If $860 is invested for one year at 11% simple interest, how much interest is earned?
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3 years ago
Find the probability that in five tosses of a fair die, a 3 will appear (a) twice, (b) at most once, (c) at least two times.
Jobisdone [24]

Answer:

A) 0.1612

B) 0.8031

C) 0.1969

Step-by-step explanation:

For each toss of the die, there are only two possible outcomes. Either it is a 3, or it is not. The probability of getting a 3 on each toss is independent from other tosses. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Five tosses, so n = 5

The die has 6 values, from 1 to 6. The die is fair, so each outcome is equally as likely. The probability of a 3 appearing in a single throw is p = \frac{1}{6} = 0.167

(a) twice

This is P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{5,2}.(0.167)^{2}.(0.833)^{3} = 0.1612

(b) at most once

P(X \leq 1) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.167)^{0}.(0.833)^{5} = 0.4011

P(X = 1) = C_{5,1}.(0.167)^{1}.(0.833)^{1} = 0.4020

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.4011 + 0.4020 = 0.8031

(c) at least two times.

Either a 3 appears at most once, or it does at least two times. The sum of the probabilities of these events is decimal 1. So

P(X \leq 1) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X \leq 1) = 1 - 0.8031 = 0.1969

6 0
3 years ago
You are cutting pieces of fabric for a craft project. You need three pieces that measure 6 2/3 inches, 4 1/2inches, and 3 5/8inc
Westkost [7]

Answer:

You need 14 19/24 inches of fabric

Step-by-step explanation:

We'll need a common denominator between 2/3, 1/2, and 5/8. 24 is the least (lowest) common denominator.

3 x 8 = 24, so we multiply the numerator and denominator by 8 and  6 2/3 becomes 6 16/24ths

2 x 12 = 24, so we multiply the numerator and denominator by 12, and 4 1/2 becomes 4 12/24

8 x 3 = 24, so we multiply the numerator and denominator by 3, and 3 5/8 becomes 3 15/24.

Now we are adding 6 16/24 + 4 12/24 + 3 15/24

6 16/24 + 4 12/24 + 3 15/24 = 6 + 4 + 3 + 16/24 + 12/24 + 15/24

= 13 + 43/24 = 14 19/24

Please lmk if  you have questions.

7 0
3 years ago
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