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frutty [35]
4 years ago
10

Which pair of ratios form a proportion?

Mathematics
2 answers:
aivan3 [116]4 years ago
7 0
5:8 and 20:32
If you multiply both 5 and 8 by 4 you get 20:32
boyakko [2]4 years ago
3 0
5:8 and 20:32 would be a proportion.

Easy way to find this:
Set up the proportion as a fraction.
Use the cross product property. Multiply the diagonals and if the products of the diagonals are the same, then they are proportional.
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Simplify each expression.<br> (n into power 4)8
hram777 [196]

Answer: 64

Step-by-step explanation:

4+4=16

4+4=16

4+4=16

4+4=16

16+16+16+16=64

7 0
3 years ago
find an equation in the form y=ax^2+bx+c for the parabola passing through the points. (2,28),(4,116),(-3,88)
IgorC [24]
<h3>Answer:</h3>

y = 8x² -4x +4

<h3>Explanation:</h3>

I find it quick and easy to let a graphing calculator do quadratic regression on the given points. It gives the coefficients of the equation directly. (See attached.)

_____

If you want to do this "by hand," you can substitute each of the x and y value pairs into the equation to get three linear equations in a, b, and c. These are generally easy to solve, as the "c" variable can be eliminated right away.

<em>For x = 2</em>

... 28 = a·2² +b·2 +c = 4a +2b +c

<em>For x = 4</em>

... 116 = a·4² +4b +c = 16a +4b +c

<em>For x = -3</em>

... 88 = a·(-3)² +b·(-3) +c = 9a -3b +c

Subtracting the first and third equations from the second, we have ...

... (16a +4b +c) -(4a +2b +c) = (116) -(28) ⇒ 12a +2b = 88

... (16a +4b +c) -(9a -3b +c) = (116) -(88) ⇒ 7a +7b = 28

Dividing the first of these reduced equations by 2, and the second by 7, we have ...

  • 6a +b = 44
  • a +b = 4

Subtracting the second of these from the first gives ...

... (6a +b) -(a +b) = (44) -(4) ⇒ 5a = 40

From which we find

... a = 8

... b = 4 -a = 4 -8 = -4

We choose the first of the original equations to find c:

... c = 28 -4a -2b = 28 -4·8 -2(-4)

... = 28 -32 +8 = 4

With (a, b, c) = (8, -4, 4), the equation of the parabola is ...

... y = 8x² -4x +4

5 0
3 years ago
_____ appear to never cross or meet and are always the same distance apart
Akimi4 [234]

Answer: parallel lines

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Halp halp halp meee <br> I give brain list to best answer pwease halp
Daniel [21]

Answer:

D 17 1/4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
PLS PLS HELP, I DONT WANT TO FAIL!!
Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

8 0
2 years ago
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