Angle A corresponds to Angle OB Oc ОЕ OD none of the above

Evaluate the expression. StartFraction 9 factorial Over 3 factorial EndFraction 3 6 60,480 362,874

REY [17]

Answer:

60,480 is the correct answer.

Step-by-step explanation:

First of all, let us have a look at the formula of factorial of a number 'n':

$n! = n \times (n-1) \times (n-2) \times ...... \times 1$

i.e. multiply n with (n-1) then by (n-2) upto 1.

Keep on subtracting 1 from the number and keep on multiplying until we reach to 1.

So, $9!$ can be written as: $9 \times 8 \times 7 \times ...... \times 1$

Similarly $3!$ can be written as: $3 \times 2 \times 1$

Re-writing $9 !$ :

$9 \times 8 \times 7 \times ...... 3 \times 2 \times 1\\\Rightarrow 9 \times 8 \times 7 \times ...... 3 !$

Now, the expression to be evaluated:

$\dfrac{9!}{3!} = \dfrac{9 \times 8 \times 7 \times ..... \times 3!}{3!}\\\Rightarrow 9 \times 8 \times 7 \times 6 \times 5 \times 4\\\Rightarrow 60480$

5 0

2 years ago

Read 2 more answers

Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12

Afina-wow [57]

Hey there, hope I can help!

$\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}\cdot \frac{d}{e}=\frac{a\:\cdot \:b\:\cdot \:d}{c\:\cdot \:e} \ \textgreater \ \frac{1\cdot \:1\cdot \:dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)$

$\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)$

$\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \ \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}$

Hope this helps!

5 0

3 years ago

When the level of confidence and sample standard deviation remain the same, a confidence interval for a population mean based on

miskamm [114]

Answer:

A narrower than

Step-by-step explanation:

6 0

3 years ago

Please help me with my math homework

rosijanka [135]

1. 100 times larger than
2. 1/10
3. 1,000 times larger than
4. 1,000 times larger than
5. 1/100
6. 1/10
7. 1/10

3 0

2 years ago

If John has 1107 bars of chocolate and wants to give each of his 10 friends an even amount each, what would each friend get? Wha

Nutka1998 [239]

Divide 1107 by 10, for example:

1107/10= 110.7

The decimal point means the remainder, this means John will only get 7 chocolate bars.

If You want it split evenly between ALL of them, divide by 1107 by 11, for example:

1107/11= 100.6, which would leave six bars left, so I think the logical offer would be the first answer I gave you.

I hope this helped!

7 0

3 years ago