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Igoryamba
3 years ago
9

Angle A corresponds to Angle OB Oc ОЕ OD none of the above

Mathematics
1 answer:
Tom [10]3 years ago
3 0

Answer:

A corresponds to angle E

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Cuál es el valor que tiene x
salantis [7]

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I might be wrong double check but it's something like

Step-by-step explanation:

4x/3-40/3

(not to sure on that so don't be mad if it's wrong)

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Which point is on the circle centered at the origin with a radius of 5 units?
Aleonysh [2.5K]

Answer:

(2,√21)

Step-by-step explanation:

The circle centered at the origin has equation:

{x}^{2}  +  {y}^{2}  = 25

Any point that satisfies this equation lie on this circle.

When x=2, we substitute and solve for y.

{2}^{2}  +  {y}^{2}  = 25 \\ 4 +  {y}^{2}  = 25 \\  {y}^{2}  = 25 - 4 \\ {y}^{2}  = 21

Take square root to get:

y =  \pm \sqrt{21}

Therefore (2,-√21) and (2,√21) are on this circle.

From the options, (2,√21) is the correct answer

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3 years ago
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How do I find the answer?
Veronika [31]

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ans is nothing

plz its is a jock

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Write the equation of the line that<br> passes through (5,-7) and (0, -1)
Fiesta28 [93]

4,3,2,1,0,-1, -2, -3, -4,

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How to find the derivative of e^3㏑(x²)
vovikov84 [41]
f(x)=e^{3\ln x^2}\\\\f'(x)=e^{3\ln x^2}\cdot\dfrac{3}{x^2}\cdot2x=e^{3\ln x^2}\cdot\dfrac{6}{x}=\dfrac{6e^{3\ln x^2}}{x}\\\\\\but\ e^{3\ln x^2}=e^{\ln (x^2)^3}=e^{\ln x^6}=x^6\ where\ x\neq0\\\\therefore\ f'(x)=6x^5
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3 years ago
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