Explanation:
The two postulates of special theory of relativity
Postulate 1: The law of physics are invariant under any of inertial frame of reference.
Postulate 2: The velocity of light is remains same in each ans every frame of reference and independent of relativity.
They are differ from classical mechanics that in classical mechanics there is no change in mass and length in relative velocity but in relativistic mechanics it changes.
These two postulates implements in phenomenon like time dilation , length contraction etc.
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Try this option, the answers are marked with colour.
Using energy.
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Answer:

Explanation:
We are given that
d=0.23 mm=

Screen is placed from the slits at distance ,L=4.75 m
The bright interference fringes on the screen are separated by 1.56 cm.

1 m=100 cm
We have to find the wavelength of laser light.
We know that

Substitute the values



<h2>
Tension in ropes are 333.33 N and 566.67 N.</h2>
Explanation:
Refer the given figure showing the arrangement.
For having stability we have torque at A and B are zero.
Sum of Torques at A = 0
700 x 1 + 200 x 1.5 - Q x 3 = 0
3Q = 1000
Q = 333.33 N
Sum of Torques at B = 0
200 x 1.5 + 700 x 2 - P x 3 = 0
3P = 1700
P = 566.67 N
Tension in ropes are 333.33 N and 566.67 N.