Answer:
True
Explanation:
Standard heat of formation is the heat change that deals with the formation of 1mole at standard rates and states of the given reactants . Standard heat of formation is the difference between the enthalpy change of reactants and products.
Answer:
a) W = 46.8 J and b) v = 3.84 m/s
Explanation:
The energy work theorem states that the work done on the system is equal to the variation of the kinetic energy
W = ΔK =
-K₀
a) work is the scalar product of force by distance
W = F . d
Bold indicates vectors. In this case the dog applies a force in the direction of the displacement, so the angle between the force and the displacement is zero, therefore, the scalar product is reduced to the ordinary product.
W = F d cos θ
W = 39.0 1.20 cos 0
W = 46.8 J
b) zero initial kinetic language because the package is stopped
W -
=
-K₀
W - fr d= ½ m v² - 0
W - μ N d = ½ m v
on the horizontal surface using Newton's second law
N-W = 0
N = W = mg
W - μ mg d = ½ m v
v² = (W -μ mg d) 2/m
v = √(W -μ mg d) 2/m
v = √[(46.8 - 0.30 4.30 9.8 1.20) 2/4.3
]
v = √(31.63 2/4.3)
v = 3.84 m/s
Answer b protons and electrons
The equation that most accurately represents the model of cellular respiration is: C6H12O6 (sugar) + 6O2 (oxygen) = 6CO2 (carbon dioxide) + 6H2O (water) + energy.
<h3>
CELLULAR RESPIRATION:</h3>
Cellular respiration is the process whereby living organisms obtain energy by breaking down food molecules in their cells.
The process of cellular respiration breaks down sugar molecules (glucose) in the presence of oxygen to produce carbon dioxide and water as products, as well as energy in form of ATP.
Therefore, the equation that most accurately represents the model of cellular respiration is: C6H12O6 (sugar) + 6O2 (oxygen) = 6CO2 (carbon dioxide) + 6H2O (water) + energy.
Learn more about cellular respiration at: brainly.com/question/12671790?referrer=searchResults