Question

An electron is moving at 2.02.0 ×× 105m/s105 m/s in the positive y direction. The magnetic force on the electron is 3.03.0 ×× 1010−12−12 ????N in the negative-z direction. What is the magnitude and direction of the magnetic field?

Answer 1

Answer:

The magnitude and direction of the magnetic field is 93.63 T in negative x direction.

Explanation:

Given;

speed of the electron in positive y direction, v = 2.0 x 10⁵ m/s

magnetic force on the electron, F in negative z direction = 3.0 x 10⁻¹² N

The magnitude of the magnetic force is given by;

F = Qv x B

B = F / Qv

$B = \frac{3*10^{-12}}{ (1.602*10^{-19})(2*10^5)}\\\\B = 93.63 \ T$

The direction of the magnetic field is is as;

Based on the direction of magnetic force (negative z direction), the charge will be directed into negative y-direction because electron is negatively charged. Thus, the direction of the magnetic field will be in the negative x-direction

$F_{(-z)}= Q_{(-y)}V* B_{(-x)}$

Therefore, the magnitude and direction of the magnetic field is 93.63 T in negative x direction.