One newton equals 0.225

Part 1: A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the en

Anit [1.1K]

1) c. 2 m/s

Explanation:

The relationship between frequency, wavelength and speed of a wave is

$v=\lambda f$

where

v is the speed

$\lambda$ is the wavelength

f is the frequency

For the wave in this problem,

f = 4 Hz

$\lambda=0.5 m$

So, the speed is

$v=(0.5 m)(4 Hz)=2 m/s$

2) a. 2.8 m/s

The speed of the wave on a string is given

$v=\sqrt{\frac{T}{\mu}}$

where

T is the tension in the string

$\mu$ is the linear mass density

In this problem, we have:

$T=2 \cdot 4 N=8 N$ (final tension in the rope, which is twice the initial tension)

$\mu = 1 kg/m$ --> mass density of the rope

Substituting into the formula, we find

$v=\sqrt{\frac{8 N}{1 kg/m}}=2.8 m/s$

5 0

3 years ago

A camera employs a ............................... lens to form...................... images. a. converging .... real b. converg

olga2289 [7]

Answer:

b

Explanation:

4 0

3 years ago

Help a girl out ?! Plz ill give brainlest

shepuryov [24]

Answer:

I am pretty sure it is B.

Explanation:

I hope this helped if it didn't I am truly sorry

5 0

3 years ago

Read 2 more answers

A fixed system of charges exerts a force of magnitude 18 n on a 9.0 c charge. the 9.0 c charge is replaced with a 4.0 c charge.

laila [671]

According to the law of gravitational force:
the force between any two objects is directly proportional to the masses of the objects and inversely proportional to the square of the distance between these two objects.

Based on this:
if a 9 c charge is replaced with a 4 c charge while the distance between the charges is kept constant:
18/9 = F/4
2 = F/4
F = 2 x 4 = 8

7 0

3 years ago

An aircraft flying at a steady velocity of 70 m/s eastwards at a height of 800 m drops a package of supplies.

iren2701 [21]

The motion of the package can be described as the motion of a projectile,

given that it has an horizontal velocity and it is acted on by gravity.

a) $\vec{v}$ = 70·i

b) The package will reach ground in approximately 12.77 seconds.

c) The speed of the package as it lands is approximately 145.51 m/s.

d) The path of the package based on a stationary frame of reference is parabolic

e) The path of the package as seen from the plane is directly vertical downwards

Reasons:

Velocity of the aircraft = 70 m/s

Direction of flight of the aircraft = Eastward

Height from which the aircraft drops the package, h = 800 m

a) The initial velocity of the package, $\vec{v}$ = 70·i

b) The time it will take the package to reach the ground, t, is given by the formula;

$\displaystyle h = \mathbf{\frac{1}{2} \cdot g \cdot t^2}$

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore;

$\displaystyle t = \mathbf{\sqrt{ \frac{2 \cdot h}{g} }}$

Which gives;

$\displaystyle t = \sqrt{ \frac{2 \times 800}{9.81} } \approx \mathbf{12.77}$

The time it will take the package to reach the ground, t ≈ 12.77 seconds

c) The vertical velocity just before the package reaches the ground, $v_y$ , is given as follows;

$v_y^2$ = 2·g·h

Therefore;

$v_y$ = √(2·g·h)

Which gives;

$v_y$ = √(2 × 9.81 × 800) ≈ 125.28

$v_y$ ≈ 125.28 m/s

Which gives; $\vec{v}$ = 70·i - 125.28·j

Therefore, |v| = √(70² + (-125.28)²) ≈ 143.51

The speed of the package as it lands, |v| ≈ 143.51 m/s

d) The motion of the package that includes both horizontal and vertical motion is a projectile motion.

Therefore;

The path of the package is the path of a projectile, which is a parabolic shape.

e) As seen by someone on the aeroplane, the horizontal velocity will be

zero, therefore, the package will appear as accelerating directly vertical

downwards.

Learn more about projectile motion here:

brainly.com/question/1130127

6 0

2 years ago