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lesya [120]
4 years ago
14

Technician A says that battery corrosion is commonly caused by spilled electrolyte. Technician B says that battery corrosion is

commonly caused by electrolyte condensation from gassing. Who is correct?
Physics
1 answer:
klio [65]4 years ago
3 0

Answer:

B is correct

Explanation:

Battery contains sulfuric acid H2SO4. As the battery cools and eats with the running of the motor, hydrogen gasses is released from electrolytic reactions and escapes through the vents. it mixes with other particulates. The mixtures react at the electrical terminals of the battery and corrosion is formed.

Corrosion can be prevented by the addition of anti corrosion gel. It can also be removed by scrubbing the terminals with a hard brush

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An object is thrown straight down with an initial speed of 4 m/s from a window which is 8 m above the ground. Calculate: a) The
frosja888 [35]

Answer:

0.41s

8.01m/s

Explanation:

Using the formula; v = u + at

Where;

u = initial velocity (m/s)

v = final velocity (m/s)

t = time (s)

a = acceleration (m/s²)

According to the provided information, u = 4m/s, s = 8m,

V = u + at

4 = 0 + 9.8t

4 = 9.8t

t = 0.41s

b) v = u + at

v = 4 + 9.8(0.41)

v = 4 + 4.018

v = 8.018m/s

8 0
3 years ago
A sprinter speeds up to 3 m/s during the last 2 seconds of the race with an
quester [9]

Answer:

<em>The initial speed of the sprinter was 2.2 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

The following relation applies:

v_f=v_o+at

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The sprinter speeds up from an unknown initial speed to vf=3 m/s in t=2 seconds with an acceleration of a=0.4~m/s^2.

To find the initial speed, we solve the equation for vo:

v_o=v_f-at

Substituting the values:

v_o=3-0.4*2

v_o=3-0.8

v_o=2.2~m/s

The initial speed of the sprinter was 2.2 m/s

4 0
3 years ago
Can someone please answer how to convert mass into weight?
Rasek [7]

Answer:

To find the weight of something, simply multiply its mass by the value of the local gravitational field, and you get a result in newtons (N). For example, if your mass is 50 kg (about 110 pounds), then your weight is (50) (9.8). The point that must be overwhelmingly emphasized is that weight is a force.

Explanation:

4 0
3 years ago
What is the probability of randomly selecting a z-score less than z = 2.25 from a normal distribution?
Vanyuwa [196]

The probability of randomly selecting a z-score less than z = 2.25 from a normal distribution is 0.8944

Probability is the branch of arithmetic concerning numerical descriptions of ways in all likelihood an occasion is to occur, or how probably it's far that a proposition is genuine. The possibility of an event is a number between zero and 1, wherein, more or less talking, zero suggests the impossibility of the event and 1 shows the truth.

Probability = the range of methods of achieving achievement. the total range of viable results. As an example, the chance of flipping a coin and it being heads is ½, due to the fact there's 1 way of having a head and the full number of possible effects is two (a head or tail). We write P(heads) = ½ .

A probability is a range that reflects the danger or chance that a particular event will occur. Chances can be expressed as proportions that vary from 0 to at least one, and they also can be expressed as probabilities ranging from zero% to 100%.

Learn more about probability here brainly.com/question/24756209

#SPJ4

4 0
2 years ago
The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away fr
WARRIOR [948]
In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
y_n= \frac{n \lambda D}{a} (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
\lambda is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem, 
D=37.0 cm=0.37 m
\lambda=530 nm=5.3 \cdot 10^{-7} m
while the distance between the first and the fifth minima is
y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m (2)

If we use the formula to rewrite y_5, y_1, eq.(2) becomes
\frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m
Which we can solve to find a, the width of the slit:
a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}=  1.57 \cdot 10^{-3} m=1.57 mm

7 0
4 years ago
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