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3 years ago

12

Help a girl out ?! Plz ill give brainlest

2 answers:

shepuryov [24]3 years ago

5 0

Answer:

I am pretty sure it is B.

Explanation:

I hope this helped if it didn't I am truly sorry

Rashid [163]3 years ago

3 0

Answer: A.

Explanation: If you move it from A to D look closely its a straight line.

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Convert the following in to SI units without changing its values<br> a. 4000 g <br>b. 2.4 km

lana66690 [7]

hi <3

i believe i explained this answer properly in my last answer but it would be 4kg and 2400m as these are the SI units for these values.

hope this helps :)

3 0

3 years ago

Read 2 more answers

What distance does light travel in water, glass, and diamond during the time that it travels 1.0 m in vacuum? the refractive ind

alexdok [17]

We are given with
distance traveled through vacuum = 1.0 m
refractive index of water = 1.33
refractive index of glass = 1.50
refractive index of diamond = 2.42

distance traveled through water is = 1.0/1.33 = 0.75 m
distance traveled through water is = 1.0/1.50 = 0.67 m
distance traveled through water is = 1.0/2.42 = 0.41 m

8 0

4 years ago

Read 2 more answers

You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th

PolarNik [594]

<u>Answer:</u> The Young's modulus for the wire is $6.378\times 10^{10}N/m^2$

<u>Explanation:</u>

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

$Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}$

where,

Y = Young's Modulus

F = force exerted by the weight = $m\times g$

m = mass of the ball = 10 kg

g = acceleration due to gravity = $9.81m/s^2$

l = length of wire = 2.6 m

A = area of cross section = $\pi r^2$

r = radius of the wire = $\frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m$ (Conversion factor: 1 m = 1000 mm)

$\Delta l$ = change in length = 1.99 mm = $1.99\times 10^{-3}m$

Putting values in above equation, we get:

$Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2$

Hence, the Young's modulus for the wire is $6.378\times 10^{10}N/m^2$

3 0

4 years ago

A toy car moves 8 min 4 s at the constant velocity. What is the car's velocity?

Schach [20]

Explanation:

<u>Formula:</u>

$velocity = (d \div t)$

<u>d = distance given</u>

<u>t</u><u> </u><u>=</u><u> </u><u>the amount of time </u><u>given</u>

<u>Substitute the given values into the formula for velocity</u><u>:</u>

$v = 8 \div 4$

velocity is shortened for v.

8 (distance) divided by 4 (time) equals the velocity.

<u>Solve:</u>

$2 = 8 \div 4$

The velocity of the toy car equals: B. 2 m/s.

6 0

2 years ago

When a 4-kg ball is thrown upwards at 40 m/s, at what

arlik [135]

Answer:

the height of the potential energy is 3,200 J

Explanation:

The computation of the kinetic energy is shown below:

Kinetic energy = 1 ÷ 2 × mass × velocity^2

= 1 ÷ 2 × 4 kg × 40 m/s^2

= 3,200 J

Hence the height of the potential energy is 3,200 J

4 0

3 years ago