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alina1380 [7]
3 years ago
12

WILL MARK YOU BRAINLIEST

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0

Answer:

see in the picture, we have:

P is the midpoint of AB

Q is the midpoint of CD

=> PQ is the median line of the trapezoid ABCD

=> PQ = (BC + AD)/2 = (54 + 33)/2 = 43.5

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How do you solve this? Please helppp what’s the answer???
ANEK [815]

Answer:

I won't be able to give you a numerical answer but that's not what your question's asking anyway. Just put a dot at the coordinates (0,-3) and one at (-2,3) and connect them. That's your first line. For the second question put a dot at the intersections (0,1) and one at (-4,-3) and connect them. You should be able to find a point where the two lines intersect. That's the point you need. If you still can't find it, then continue the lines or message me at riztofu on insta. I'll solve your question then.

Step-by-step explanation:

4 0
3 years ago
Please help me with this
3241004551 [841]

Answer:

Will

Step-by-step explanation:

Katie runs 8 feet per second

Stephanie runs 10.88 feet per second

Liz runs 12.9 feet per second

Will runs 13.45 feet per second

3 0
2 years ago
Which of the following does NOT have any rectangular faces
Sveta_85 [38]
B. A hexagonal prism would have every side be a hexagon or a triangle.
6 0
4 years ago
Use the​ power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonome
Delicious77 [7]

Step-by-step explanation:

Sin^2 (x) * Cos^2 (x) = {[1 - cos (2x)]/2}*{[1 + cos (2x)]/2}

Sin^2 (x) * Cos^2 (x) =[ 1 - cos^2 (2x)]/4

Sin^2 (x) * Cos^2 (x) = (1/4) - (1/4) * cos^2 (2x)

Sin^2 (x) * Cos^2 (x) =  (1/4) - (1/4) * {[1 + cos (2*2x)]/2}

Sin^2 (x) * Cos^2 (x) =  (1/4) - (1/8) * [1 + cos (4x)]

Sin^2 (x) * Cos^2 (x) =  (1/4) - (1/8) - (1/8)* [cos (4x)]

Sin^2 (x) * Cos^2 (x) =  (1/8) - (1/8)* [cos (4x)]

6 0
3 years ago
In circle F with m \angle EFG= 122m∠EFG=122 and EF=16EF=16 units, find the length of arc EG. Round to the nearest hundredth.
kow [346]

Given:

In circle F, m\angle EFG=122^\circ,\ EF=16 units.

To find:

The length of arc EG.

Solution:

It is given that, m\angle EFG=122^\circ,\ EF=16 units. It means the central angle of arc EG is 122 degrees and the radius of the circle F is 16 units.

Formula for arc length is:

s=2\pi r\times \dfrac{\theta}{360^\circ }

Where, r is the radius and \theta is the central angle in degrees.

Putting r=16,\ \theta=122^\circ,\ \pi=3.14, we get

s=2(3.14)(16)\times \dfrac{122^\circ}{360^\circ }

s=100.48\times \dfrac{61}{180}

s=34.0515556

s\approx 34.05

Therefore, the length of arc EG is 34.05 units.

6 0
3 years ago
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