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denis-greek [22]
3 years ago
11

Guys, I really need that help T-T.

Mathematics
2 answers:
hjlf3 years ago
8 0
I’m not good at explaining but I’ll try.

Legs: 5, √3. Hypotenuse: √28

So your legs are: a and b, and ur hypotenuse is c

a^2+b^2=c^2
Which means

5^2+√3 has to equal to √28^2.

Let’s solve it

5^2+√3^2= √28^2

= 25+3=28

28=28

So that is a right triangle.


enyata [817]3 years ago
3 0

First to Answer:

The triangle would be a cute Scalene Triangle!

<u>Here's all that you really can do with solving that</u>

√28 =5.29150262213

√8 = 2.82842712475

Side a = 2.8

Side b = 5

Side c = 5.2

Angle ∠A = 31.788° = 31°47'18" = 0.55481 rad

Angle ∠B = 70.167° = 70°10'0" = 1.22464 rad

Angle ∠C = 78.045° = 78°2'42" = 1.36214 rad

Area = 6.84817

Perimeter p = 13

Semiperimeter s = 6.5

Height ha = 4.89155

Height hb = 2.73927

Height hc = 2.63391

Median ma = 4.9051

Median mb = 3.34515

Median mc = 3.10805

Inradius r = 1.05357

Circumradius R = 2.65764

Vertex coordinates: A[0, 0] B[5.2, 0] C[4.25, 2.63391]

Centroid: [3.15, 0.87797]

Inscribed Circle Center: [3.7, 1.05357]

Circumscribed Circle Center: [2.6, 0.55051]

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Answer:

-4

Step-by-step explanation:

ok negative times negative = positive

and factors of 24 are

1,2,3,4,6,8,12,24

4 x 6 are the two consecutive EVEN numbers

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-4 x -6 = 24

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3 years ago
Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar
bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\

A. P(x=6)

P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\

B. P(x≥10)

P(x\geq10)=1-P(x

P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\

P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\

P(x\geq10)=1-(0.0008+0.0063+0.0251+0.0641+0.1175+0.1645+0.1828+0.1654+0.1241+0.0781)\\\\P(x\geq10)=1-0.9287=0.0713

C. The expected value (mean) and standard deviation of this binomial distribution can be calculated as:

E(x)=\mu=n\cdot p=25\cdot 0.25=6.25\\\\\sigma=\sqrt{np(1-p)}=\sqrt{25\cdot 0.25\cdot 0.75}=\sqrt{4.69}\approx2.17

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The probability is 1/6, 16%, or 0.16

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Step-by-step explanation:

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Kono Dio Da!!!

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